The answer to your question is 12.6 because you multiply the .400 times .750 and then you take the answer (0.3) and multiply this times the molar mass of NaF (42) and get 12.6.
I suppose that this solution doesn't exist.
1.17 grams :)
The gram formula mass of CaCl2 is 110.99. By definition, each liter of 0.700 M CaCl2 contains 0.700 gram formula masses of the solute. Therefore, 2.00 liters of such solution contain 1.400 formula masses of the solute, or 155 grams, to the justified number of significant digits.
The cadmium ion has a 2+ charge and each fluoride ion has a 1- charge, so two fluoride ions are needed to balance the 2+ charge of cadmium. Two F- ions provide a total negative charge of 2- to balance the 2+ charge of cadmium.
600 mL of 0,9 % sodium chloride: 6 x 0,9 = 5,4 grams NaCl
I suppose that this solution doesn't exist.
Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.
25 mL
105 g
source document
10
35.38g
25
The needed mass is 35,549 g.
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
1.17 grams :)
4 moles or 160 g NaOH is required for one litre solution.