46 grams of sodium is 2 moles. 2 mol of sodium forms 1 mol of sodium oxide. So it makes 62 g of sodium oxide.
If the reaction is:6 Na + 2 O2 = 2 Na2O + Na2O2This mass is 3,83 g sodium.
32,895 g of triuraniumoctaoxide (U3O8).
1654 grams exactly
How do you find the mass ratio. And how many grams fluorine is made at decomposition.
The molecular mass of sodium oxide is 61.97894.
62 grams a+
62 grams a+
If the reaction is:6 Na + 2 O2 = 2 Na2O + Na2O2This mass is 3,83 g sodium.
2 Na + O2 + 2 NaO 78 g of NaO
155.2 g
16 grams? I would purpose that this has a little something to do with the law on conservation of mass. I could always be wrong though...
32,895 g of triuraniumoctaoxide (U3O8).
234 grams
1654 grams exactly
How do you find the mass ratio. And how many grams fluorine is made at decomposition.
The molecular mass of sodium oxide is 61.97894.
The formula mass of sodium oxide, Na2O is 2(23.0)+16.0 = 62.0 Amount of sodium oxide = 7.94/62.0 = 0.128mol