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The preferred geometry of molecule BrF3 or bromine trifluoride is a planar "T-shaped" molecule. This is due to the two lone pairs of electrons on bromine, which cause a repulsion from the fluorine atoms.
no
no
Octahedral is the edcc geometry and the molecular geometry is square pyramidal
Br is the chemical symbol for Bromine. There are three fluorine atoms covalently bonded, so they form triflouride. The full name is then bromine fluoride.
It is five because there is a total of five electron pairs around the bromine atom.
sp3d2, this accounts for all 6 electron domains found around the central Br atom. Verify by checking the Lewis dot configuration. Br has 4 bonded electron domains and 2 lone pairs. Therefore the hybridization of the central atom in BrF4 is sp3d2
Sp
BrF3
Formula: BrF3
Formula: BrF3
There are none
It is hard to say, because BrF is readily disproportioning into Br2,(l) and BrF3,(l) according to:3 BrF → BrF3 + Br2Bromine trifluoride, BrF3, is boiling at 125.72 °CCompared with Chlorine fluoride: this, ClF, is an (also) unstable brownish yellow gas (with boiling point 5°C)
The preferred geometry of molecule BrF3 or bromine trifluoride is a planar "T-shaped" molecule. This is due to the two lone pairs of electrons on bromine, which cause a repulsion from the fluorine atoms.
Br +3, balanced by 3 fluorines each with -1.
The complete decomposition reaction is as follows:2 BrF3 → Br2 + 3 F2 , so 2 moles BrF3 will give 1 mole Br2 , hence 0.248 mole gives 0.124 mole Br2
well BrF3 will auto dissociate to give BrF4- + BrF2+ ...the KF will give a F- to the BrF3 obviously this giving is really due the higher electronegativity of the fluorine thus their will be an increase in the amounts of BrF4- in solution .Using the solvent-system definition of an acid or base.Any specie (molecule ,ion)which increases the anionic or negatively charged amounts of species in solution is a base.So KF definitely behaves as a base. You can use this same reasoning for SnF4 and try and figure that one out on your own.good luck .