4.5 moles NaCl = 4.5000000000001 formula units NaCl
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4.5 moles of NaCl would contain 4.5 x (6.02 x 1023) formula units.
= 2.7 x 1024 formula units
molar mass of NaCl = 23+35.5 = 58.5 g/mol
mass = (No. of moles)*(Molar Mass) = 4*58.5 = 234 grams.
The answer is: 4,5 x 58,44 = 262,98 grams.
The answer is 54,199.1023.
45/94.2 is 0.4777 moles
We just use stoichiometry. The molecular formula for sodium chloride is NaCl. First we must find the molar mass of NaCl, using the molar masses of each element in the compound. So, 23 g/mol of Na + 36 g/mol of Cl = 58 g/mol of NaCl. Next, we take the amount of grams you have (26 grams) and divide it by the molar mass of NaCl to find the number of moles in your sample. 26 g NaCl / 58 g/mol of NaCl = .45 mol NaCl. Finally, we convert that to the number of NaCl molecules in a mole by multiplying .45 moles by 6.02x1023. This equals 2.7x1023 molecules. Because, technically, NaCl is made up of 2 atoms per molecule, you can multiply that by 2, giving 5.7x1023 atoms.
Yes
stp= 22.4 dm3, 1L = 1 dm3 1mole ---> 22.4dm3 xmole ---> 45dm3 45/22.4 = 2.001 moles
The moles number of water 12; the chemical formula is KAl(SO4)2.12H2O.
.45 what? Grams? in that case its 0.45 grams of salt
Nope
.45 mol
45 grams, since the atomic mass of water is 18g.18 * 2.5 = 45
The molecular mass of fluorine gas, F2 is 2(19.0) = 38.0Amount of F2 = mass of sample/molar mass = 9.5/38.0 = 0.25mol There are 0.25 moles of fluorine in a 9.5g pure sample.
You have to evaporate (by open boiling) 45 mL of the 75 mL 2M NaCl solution thus reducing the volume to 30 mL 5M NaCl.
45 mg contains approximately 1.956 moles of atomic sodium.