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2,26 Kj are necessary
It takes 4.186 Joules to heat one gram of water by 1-degree Celsius. 4.186 * 4000 = 16,744 Joules to heat 4 kilos of water by 1-degree. 16,744 * 70 = 1,172,080 Joules. The above assumes that one litre of water weighs exactly 1 Kilogram.
The unit for the heat of vaporization is J/g or Joules per gram of material. The amount of energy required = mass * heat of vaporization = 5.0 g * 5.0 J/g = 25.0 J (Q.E.D.)
Kinetic energy = 1/2mv2, where kinetic energy is measured in Joules, mass in grams, and velocity in m/s.
40.79 H2O kj/moles x 1 moles/18 grams= 2.266/1000=0.002266 joules/grams
The answer is 55,117 kJ.
A: Energy is measured in joules and kilojoules. One joule is the amount of energy needed to lift 100 grams to 1 kiliogram.
Voltage is electrical pressure and Joules is a power rating so other info is needed
The specific latent heat/ latent heat of fusion of ice is 333.55 J/gtherefore by using the equation E=mLE = 54 * 333.55= 18011.7 JTherefore the energy needed to melt 54 grams of ice at its melting point which is keeping it at 0 degrees Celsius is 18011.7 Joules.
2,26 Kj are necessary
No, a Joule is a unit of energy. Mass is measured in kilograms (or grams)
The object's kinetic energy is 2,500 joules.
9.1x10^2J
5.2
It takes 4.186 Joules to heat one gram of water by 1-degree Celsius. 4.186 * 4000 = 16,744 Joules to heat 4 kilos of water by 1-degree. 16,744 * 70 = 1,172,080 Joules. The above assumes that one litre of water weighs exactly 1 Kilogram.
0.131 joules/gram'C x 1.3 grams x (46-25)'C = 3.5763 joules
46 calories (or 192, 464 joules) for each Celsius degree.