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How many liters of water should be added to 18 liters of a 14 bleach solution so that the remaining solution contains only 10 bleach?
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What is the molarity of a solution that contains 0.202 moles KCl in 7.98 liters of solution?
The molarity is 0,025.
What is the molarity of a solution that contains 1.1 of lithium in 0.5 liters of solution?
If 1,1 is grams the molarity is 0,317.
What is the molarity of a solution that contains 4.53 moles of lithium nitrate in 2.85 liters of solution?
This molarity is 1,59.
What volume of 4.00 M Hcl solution contains 0.150 mol Hcl?
Molarity = moles of solute/Liters of solutionOr, for our purposes....,Liters of solution (volume) = moles of solute/MolarityVolume (liters) = 0.150 moles HCl/4.00 M HCl= 0.0375 liters = 37.5 milliliters======================
A solution contains 85.0 g of NaNO3 and has a volume os 750 mL find the molarity of the solution?
Molarity is mols of solute over liters of solution. 85.0g NaNO3 (1mol/85g ) = 1mol 750ml = 0.75 Liters so, 1/0.75 = 1.3 Molar
What is the molarity of a solution that contains 0.202 moles KCl in 7.98 liters of solution?
The molarity is 0,025.
What is the molarity of a solution that contains 6.42 moles of lithium nitate in 1.75 liters of solution?
Molarity is moles of solvent divided by liters of solution, so 6.42 / 1.75 = 3.67M.
What is the molarity of a solution that contains 1.1 of lithium in 0.5 liters of solution?
If 1,1 is grams the molarity is 0,317.
What is the molarity of a solution that contains 4.53 moles of lithium nitrate in 2.85 liters of solution?
This molarity is 1,59.
What is the molarity of a solution that contains .202 mol KCI in 7.98 L of solution?
Molarity = moles of solute/Liters of solution Molarity = 0.202 moles KCl/7.98 Liters = 0.253 M KCl solution ================
What is the molarity of a solution that contains 112 grams of KOH in 2.00 liters of solution?
112/56.1056=1.996 so 2.0mole 2 moles/2 liters = 1 M
What is the molarity of 1.5 liters of an aqueous solution that contains 52 grams of lithium flouride?
1.3M
How many grams of solute are contained in 3.5 L of solution that contains 21.7 ppm of SnCl2?
There are 23.5 grams of solute contained for every 1,000,000 liters of solution that contains 21.7 ppm of SnC12. Therefore, there is 0.00008365 grams of solute in 3.5 liters of solution.Ê
What volume of 4.00 M Hcl solution contains 0.150 mol Hcl?
Molarity = moles of solute/Liters of solutionOr, for our purposes....,Liters of solution (volume) = moles of solute/MolarityVolume (liters) = 0.150 moles HCl/4.00 M HCl= 0.0375 liters = 37.5 milliliters======================
What is the molarity of a solution that contains 31.0 grams of HCl in 500cm3 of solution?
31 grams HCl (1mol/36.458g ) = 0.850 moles 500cm^3 = 0.50 Liters Molarity = moles of solute/liters of solution Molarity = 0.850mol/0.50L = 1.7 Molarity
A solution contains 85.0 g of NaNO3 and has a volume os 750 mL find the molarity of the solution?
Molarity is mols of solute over liters of solution. 85.0g NaNO3 (1mol/85g ) = 1mol 750ml = 0.75 Liters so, 1/0.75 = 1.3 Molar
How many mls of a 100mmolar glycine solution contains .005 moles of glycine?
Some conversion required. (mmolar into mol, or moles into mmol ) Molarity = moles of solute/Liters of solution 100 millimolar = 0.1 M glycine Molarity = moles of solute/Liters of solution manipulate algebraically Liters of solution = moles of solute/Molarity 0.005 mole glycine/0.1 M glycine = 0.05 Liters ( 1000 ml/1 L) = 50 milliliters of solution --------------------------------
