To dilute an 18-liter solution of 14% bleach to a 10% concentration, you need to first determine the amount of pure bleach in the original solution. The 18 liters of 14% bleach contains 2.52 liters of pure bleach (0.14 × 18). To find the total volume needed for a 10% solution, set up the equation: 2.52 liters = 0.10 × (18 + x), where x is the amount of water to add. Solving for x, you find that you need to add 7.2 liters of water.
The molarity is 0,025.
This molarity is 1,59.
If 1,1 is grams the molarity is 0,317.
Molarity = moles of solute/Liters of solutionOr, for our purposes....,Liters of solution (volume) = moles of solute/MolarityVolume (liters) = 0.150 moles HCl/4.00 M HCl= 0.0375 liters = 37.5 milliliters======================
One-half cup of bleach is equivalent to approximately 0.12 liters.
The molarity is 0,025.
Molarity is moles of solvent divided by liters of solution, so 6.42 / 1.75 = 3.67M.
This molarity is 1,59.
If 1,1 is grams the molarity is 0,317.
10% of 6L is 600 ml. 6000 / 100 * 10 = 600 ml.
A solution with a percent by volume of 0.038 contains 0.038 liters of solute dissolved in 100 liters of solution. This means that 0.038% of the total volume is the solute.
Molarity = moles of solute/Liters of solution Molarity = 0.202 moles KCl/7.98 Liters = 0.253 M KCl solution ================
Molarity = moles of solute/Liters of solutionOr, for our purposes....,Liters of solution (volume) = moles of solute/MolarityVolume (liters) = 0.150 moles HCl/4.00 M HCl= 0.0375 liters = 37.5 milliliters======================
One-half cup of bleach is equivalent to approximately 0.12 liters.
Molar means moles per litre. Therefore, you need to divide 1.4 by 3.2 to get an answer per litre. 1.4/3.2 is 0.4375 molar.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution in liters. In this case, the molarity would be 0.15 M, which is calculated by dividing 0.45 moles by 3.0 liters.
First, convert the mass of NaNO3 to moles using the molar mass of NaNO3. Then, calculate the molarity by dividing the moles of NaNO3 by the volume of the solution in liters. Molarity (M) = moles of solute / volume of solution in liters.