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26.8125 g
15 litres
A 2M NaCl solution contains approximately 58.5g of salt. So to make two liters of a 2M solutions you would need 117g of salt dissolved in 2 liters of water.
Molarity = moles of solute/Liters of solution ( 50.0 ml = 0.05 Liters ) 0.552 M KCl = moles/.0.05 liters = 0.0276 moles of KCl
Some conversion required. (mmolar into mol, or moles into mmol ) Molarity = moles of solute/Liters of solution 100 millimolar = 0.1 M glycine Molarity = moles of solute/Liters of solution manipulate algebraically Liters of solution = moles of solute/Molarity 0.005 mole glycine/0.1 M glycine = 0.05 Liters ( 1000 ml/1 L) = 50 milliliters of solution --------------------------------
Mixing 80 liters of 15% solution and 520 liters of 90% solution will give 600 liters of 80% solution.
10 liters.
4.5 litres of a 30% solution to the appropriate quantity of the 90% solution.
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4.84
1.6
26.8125 g
15 litres
15 liters thanks a lot guys
Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============
Molarity = moles of solute/Liters of solution ( 20.0 ml = 0.02 Liters ) moles of solute = Liters of solution * Molarity 0.02 Liters * 0.800 M MgCl2 = 0.016 moles MgCl2 -------------------------------
If you had to figure out how many liters were in 1.75 kiloliters you answer would be: 1,750 liters