add 25ml more of solution
x * 20 = 100 * 25
x = 25
dissolve 10g of TCA in 100ml distilled water.
25% ammonia solution means 25g Ammonia in 100ml of water. To convert it into moles i.e for 1000ml solvent, 25x100=250 which means 250g of ammonia is present in 1000ml of water to make a 25%solution. To convert it into molar solution we will divide 250 by the molecular mass of ammonia i.e 17. 250/17= 14.71M This means that 25% ammonia solution contains 14.71 moles of ammonia. Now we will use the formula M1V1=M2V2 Let's say we want to make 10 molar solution in 500ml water. Then, M1=14.71 V1=? M2=10 V2=500 Putting values in the above equation: 14.71xV1 = 10x500 V1 = 10x500 / 14.71 = 340ml We will take 340ml of the 25% ammonia solution and make the volume up to 500ml with water. This will be our 10 molar solution of Ammonia.
10g of K2CO3 in 100mL
3 percent alcohol
percent concentration = (mass of solute/volume of solution) X 100 To solve for mass of solute, mass of solute = (percent concentration X volume of solution)/100 So, mass of solute = (10% X 100mL)/100 = 10g
0.06% W/V = 0.06g / 100ml = 60mg/100ml = 0.6mg/ml
Very simply 1g of ammonium thiocyanate and 100g (100ml) of water!
Very simply 2g of ferric chloride and 100g (100ml) of water!
dissolve 10g of TCA in 100ml distilled water.
50 g
Take 10 gm oF KI dissolve it in 100ml.
4.0%
It means that 100mL of solution has 75g of solute dissolved in it.
Weigh 10g of the given sample and dissolve it in 100ml of water, it forms a 10% solution of that sample.