Molecular mass of AlCl3 = 27.0 + 3(35.5) = 133.5
Amount of AlCl3 = 400/133.5 = 3.00mol
The ratio of Cl to AlCl3 is 3:1.
Amount of Cl = 3 x 3.00 = 9.00mol
.21 moles/liter * .0655 L = 0.013755 moles AlCl3 .013755 * 3 moles Cl / 1 mole AlCl3 = 0.041265 moles Cl * avagadro's number = number of chloride ions
lattice energy
1 mole in 70 g of Cl2
The answer is 40.1 g AlCl3, assuming that the questioner meant 27.0 g and 32.0 g (the units weren't provided in the question). It was calculated as follows: 27.0 g of Al is 27.0 g/27.0 g/mol = 1.00 mol of Al. 32.0 g of Cl is 32.0 g/35.45 g/mol = 0.903 mol of Cl. Aluminium chloride has the molecular formula of AlCl3, therefore it takes three moles of chlorine to form one mole of aluminum chloride, or in this case, it would take 3.00 mol of Cl to react with 1.00 mol of Al. It is clear that the amount of AlCl3 that can be formed is limited by the moles of Cl available, specifically the maximum number of moles of AlCl3 that can be formed is 0.903 mol/3 = 0.301 mol. 0.301 mol AlCl3 is equivalent to: 0.301 mol AlCl3 x 133.35 g AlCl3/mol = 40.1 g AlCl3.
Avogadro's numbers worth. I mole of anything is, 6.022 X 1023 atoms ----------------------------
It does NOT form molecules. When AlCl3 'breakdown ' it form the IONS Al^(3+) & 3 Cl^(-) AlCl3(s) IS a molecule.
10 grams of AlCl3 contains a certain number of moles in particles.1 mole of AlCl3 weighs (26.9815386+(3*35.453)=133.3405386), let's round that to 133.3405 grams.So 10 grams = 10/133.3405 = 0.075 mole of AlCl3 (rounded), but for each AlCl3 we have, you get 4 ions (1 Al3+, 3Cl-). So we have 0.075 moles, but we get 4 times as many ions. 0.075*4=0.3 mole1 mole = 6.022141x1023 (Avogadro's Number)0.3 mole = 1.81x1023 ions
.21 moles/liter * .0655 L = 0.013755 moles AlCl3 .013755 * 3 moles Cl / 1 mole AlCl3 = 0.041265 moles Cl * avagadro's number = number of chloride ions
0.355 M AlCl3 (3 moles Cl/1 mole AlCl3)= 1.07 M Cl================Naturally.0.355 M Al============add1.43 M total=========
lattice energy
A mole of calcium has 6.022 X 1023 calcium ions.
1 mole in 70 g of Cl2
Answer: 12,044 282 58.1023 ions.
A mole of a substance is 6.022X1023 atoms, molecules, or formula units of a substance.
108
1 mole of EDTA will chelate with 1 mole of Ca2+ ions or 1 mole of Fe2+ or Fe3+ ions.
3(2.6) = 7.8 moles of ions