A 1 M solution of glycerol indicates that there is 1 mole of solute per liter of solution. So in 1 liter, there is one mole, or 6.022 E 23 molecules.
In a 1M solution of glycerol, there will be 1 mole of glycerol in 1 liter of solution. One mole of glycerol contains approximately 6.022 x 10^23 molecules. Therefore, there are approximately 6.022 x 10^23 molecules of glycerol in 1 liter of a 1M solution.
Haha just had this on my take home bio quiz q 19. It is 6.02 x 10'23
6.02 x 10^23 aka 1 mole
To prepare a 10mM solution of Tris-HCl, you would weigh out the appropriate amount of Tris-HCl powder using a balance and dissolve it in water to make a final volume of solution. For example, to make 1L of 10mM Tris-HCl solution, you would need to dissolve 0.121g of Tris-HCl in 1L of water.
To make a 1M KH2PO4 buffer solution, dissolve 136.09 grams of KH2PO4 in enough water to make a final volume of 1 liter. Always ensure that the pH of the solution is adjusted to your desired value using an appropriate acid or base, such as NaOH or HCl.
The molar mass of EDTA is 372.24 g/mol. To calculate the molarity of the stock solution, you need to divide the mass of EDTA used (18.612 g) by its molar mass and then multiply by the dilution factor (50x). Finally, divide this result by the final volume (1 L) to get the final concentration in mol/L.
0.002M HCl means 0.002 moles HCl in 1L solution. Therefore 0.02 moles HCl in 10L solution. pH = 2-log2 = 2-0.3010 = 1.6990
No, molarity and normality are not the same in K2Cr2O7. Molarity is the concentration of a solution expressed in moles of solute per liter of solution, while normality is a measure of concentration based on the equivalents of a solute in a solution. In the case of K2Cr2O7, as it has more than one ion that can undergo reaction, the normality would be different from the molarity.
2g
1.3g
The solution to the Largo Winch latch puzzle is as follows: Key: 1-Ist latch from top R-Right 2-2nd latch from top L-Left 3-3rd latch from top 4-4th latch from top Solution: 1L-2L-1L-3L 1R-2R-1R-3L 1L-2L-1L-4L 1R-2R-1R-3R 1L-2L-1L-3R 1R-2R-1R-4L 1L-2L-1L-3L 1R-2R-1R-3L 1L-2L-3L
1mL of water = 1cm3 but that conversion is dependent on water's density. If your solution was water in water (ha ha) then 1L = 1000 mL = 1000cm3 = 1 million mm3 (http://www.google.com/search?q=1L+to+cubic+mm) (http://www.google.com/search?q=1000cubic+cm+to+cubic+mm) You need to know the density of any "other" solution to accurately convert. If you meant "milliliters" then 1L = 1000mL, independent of density.
To prepare a 10mM solution of Tris-HCl, you would weigh out the appropriate amount of Tris-HCl powder using a balance and dissolve it in water to make a final volume of solution. For example, to make 1L of 10mM Tris-HCl solution, you would need to dissolve 0.121g of Tris-HCl in 1L of water.
There are 1000 milliliters in 1 liter.
3.00 M, or 3 moles per (L) "liter" calls for having 3 moles per liter of the solution. The question asks how many moles must be in 250ml of a solution that has 3 moles per Liter. You must ask yourself what percent of 1 Liter is 250mls? Since there are a thousand ml in one liter, (1000ml=1L), then 250ml is exactly 25% of a Liter, or .25L. So, 250ml can only hold 25% of the 3.00 Molarity. Meaning that you multiply 3 x .25 and get .75 moles.
there are 1000mL in 1L
1L = 1000mL 600mL x 1L/1000mL = 0.6L
Gram percent is the number of grams of a solute per 100 grams of a solution. For example, if a solution of NaCl and water was said to have a 0.02g% of NaCl, this would mean that for 100g of saline solution, 0.02 of those grams are salt. Since 1L of water weighs 1kg (at normal conditions), there would be .2g of NaCl in 1L of a 0.02g% NaCl solution.
Dissolve 294,185 g of potassium dichromate in 1L demineralized water.
MW 74.5, 1M solution requires 74.5g in 1L, 5M solution requires 74.5x5 = 372.5g in 1 L. You would need 93.1g KCL to make 250mL 5M solution