the mass of the EDTA used to prepare 1L oi solution is 18.612g. The formula mass is 372.24 g/mol.
Therefore concentration of the 50x solution is:
18.612 g 1 mol
----------- x --------- = 0.050000 mol/L = 50.000 mM
1L 372.24 g
A 1 mole glucose solution means that there would be 1 mol/liter. There is only .075 liters, so there is only .075 moles present. .075 moles in 400 milliliters is a .075 to .4 ratio. By expanding the ratio, it is found that there are .1875 moles to 1 liter, making the final concentration 0.1875 M.
Are you sure you mean 0.211 m not 0.211 M Is the concentration molality or molarity? If 55 ml of a 0.211 m NaOH is diluted to a final volume of 125 ml what is the concentration of NaOH in the diluted solution?NaOH not NaHO the compound is Sodium hydroxide Molar mass of NaOH = 23 + 16+ 1 = 40 0.211 moles of NaOH = 0.211 * 40 = 8.44 grams of NaOH per liter of solution 55 ml = 0.055 Liter 8.44 grams of NaOH per liter of solution * 0.055 liter = 0.4642 g of NaOH Moles of NaOH = 8.44 ÷ 40 = 0.211 moles 0.211 moles of NaOH in 125 ml = 0.211 moles ÷ 0.125 L = 1.688 m
v1= initial volume c1= initial concentration v2= final volume c2= final concentration For example, you have 10mL of an unknown substance with a concentration of 0,5mol/L. If you add 50mL, what will the final concentration be. V1= 10mL C1= 0,5mol/L V2= 60mL C2= x 10/0,5=60/x You must start by putting everything in the same mesure. We'll use mL here. So 0,5-->1000mL= 50-->10mL 50x60= 300 300/10= 30 30 is your C2
4.83g of nitrous acid ( HNO2 )is added to water to make a final solution of 480.0ML.
The key formula for solving a dilution problem is M1V1=M2V2 (alternately, MAVA=MBVB) where concentration is M (measured in Molars, a unite of concentration-->Molars=moles solute/Liters solution) and the volume of solution is V. M1V1 represents the inital conditions (pre-dilution), and M2V2 denotes the final conditions (post-dilution). Plug in the three values you know to find the fourth value, which you are solving for. Ex. 750mLs of a 0.5 M NaC2H3O2 solution is diluted with 250mL of H2O. What is the new concentration of NaC2H3O2? Answer: (0.5M)x(.750L)=(MB)x(.750L+.250L) 0.375ML=(MB)x(1L) MB=0.375M
The concentration is 1 mol/L or 5,611 g KOH/100 mL solution.
calculate final molarity of the solution if 11ml of 5m solution is made up to 20ml
Yes
sent them to concentration camps and death camps
You need to add the 50ul stock solution to 1200ul of distilled water to produce 1250ul of solution with a concentration of 2ul per ml.
13.6% methanol solution.
No, he never visited the concentration camps. He did not deal with the Final Solution plan, that was mostly Himmler's work.
.48 = [OH-]
Hilter did not dicide what to do to the Jews so he took them to GETTO where then they where send to the Final place concentration camps
4.0%
The Final Soution was decided at the Wansee Conference, this idea of the Final Solution started the mass killings in the Concentration Camps.
.01 M