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Avagadro's number says there are 6.02x1023 particles of a pure substance in one mole of that pure substance. (A particle is an atom, molecule, or ion.)
(2.1 mol CO2) (6.02x1023 molecules CO2/1 mol CO2)
= (2.1)( 6.02x1023 molecules CO2) = 1.26 x 1024 molecules CO2
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What is the number of carbon atoms in 2.5 x 1021 molecules of carbon dioxide?
The formula is CO2, so there is one atom of carbon and two atoms of oxygen in each molecule.So there are 2.5x10^21 atoms of carbon in that many molecules of CO2.
How many grams of NH3 are needed to provide the same number of molecules as in 0.55 grams of SF6?
molar mass NH3 = 17 g/molmolar mass SF6 = 146 g/molmolecules in 0.55g SF6 = 0.55g x 1mol/146g x 6.02x10^23 molecules/mole = 2.27x10^21 moleculesgrams NH3 needed = 2.27x10^21 molecules x 1mol/6.02x10^23 molecules x 17g/mol = 0.064 grams
What is the mass in grams of atom of copper and how many atom are there 1g of copper?
6.022*10**23 atoms / mol = avagadro's constant 63.546 g / mol = atomic weight of copper 1 atom / 6.022*10**23 atoms/mol * 63.546 g/mol = 1.05523082*10**-22g 1 g / 63.546 g/mol * 6.022*10**23 atoms/mol = 9.476599629*10**21 atoms
How many grams are in 3 moles of lithium?
to get the answer just take number of moles you have and multiply it by the molecular mass of the compound which is 22g/mol in lithium oxide's case. 23mol x 22g/mol = 506 g of Li2O
How many moles of carbon are present in a 100g sample?
moles = mass (g) divided by the molecular weight (g/mol) moles = 100g/12.01
How many molecules are in 0.03 mol of carbon dioxide?
6.022 * 10^21
How many air molecules in atmosphere?
The mass of the Earth's atmosphere is 5.25x10^21 grams. If we assume the molar mass of air is approximately 29 grams per mole we get:(5.25x10^21) multiplied by Avogadro's constant (6.02x10^23) and then divided by (29 grams/ mol) = 1.09x10^44 molecules of air in the atmosphere.
3920 molecules CO2 to moles CO2?
We know for every 6.022 x 10^23 molecules, we have a mole of a substance, right? So if we have 3920molecules, we can use the above conversion factor to get: 3920 molecules CO2 x (1mol CO2/(6.022x10^23molecules CO2)) = 6.51 x 10^-21 moles CO2. There are three significant figures in this problem, from the 3929 molecules.
How many molecules of S8 would be necessary to obtain 1.000 g of S?
(6.022*10^23) * [1.000 (g) / (8 * 32.00 (g/mol)] = 2.352*10^21 molecules
What is the number of carbon atoms in 2.5 x 1021 molecules of carbon dioxide?
The formula is CO2, so there is one atom of carbon and two atoms of oxygen in each molecule.So there are 2.5x10^21 atoms of carbon in that many molecules of CO2.
How many moles of HCI do you need to react with aluminum foil if you use 15 grams of acid?
0.2550 g AlC3 (1 mol/132 g) =0.001932 mol AlCl3 0.001932 mol AlCl3 (6.022 x 10^23 molecules AlCl3/1 mol AlCl3) = 1.163 x 10^21 1.163x10^21 molecules AlCl3 (3 mol Cl/1 mol AlCl3) =3.490x10^21 Cl ions 3.490x10^21 Cl ions (1 mol/6.022 x 10^23) =5.795x10^-3 moles Cl The formula to solve this problem appears above.
How many atoms are in 5.58 mol of CO2?
In one (1) molecule CO2 there are 3 atoms ( 1 C-atom and 2 O-atoms), so in 5 molecules CO2 (5CO2) there are 5 x 3 (= 15) atoms. Thus fifteenis the answer to you.
How many out of 200 air molecules are oxygen?
Air is 21% oxygen so 21% of 200 is 42 oxygen molecules.
How many grams of NH3 are needed to provide the same number of molecules as in 0.55 grams of SF6?
molar mass NH3 = 17 g/molmolar mass SF6 = 146 g/molmolecules in 0.55g SF6 = 0.55g x 1mol/146g x 6.02x10^23 molecules/mole = 2.27x10^21 moleculesgrams NH3 needed = 2.27x10^21 molecules x 1mol/6.02x10^23 molecules x 17g/mol = 0.064 grams
How many molecules lemonade have?
aproximately 432567000
How many molecules of carbon dioxide are there in 1.0 grams of the gas?
The gram molecular mass of carbon dioxide is about 44.01 grams. By definition, this value is the number of grams of carbon dioxide that contains Avogadro's Number ("AN") of molecules. Avogadro's Number is about 6.022 X 10^23. Therefore the number of molecules in 1 gram is (1/44.01)(AN) or 2 X 10^21 molecules, to the justified number of significant digits.
How many atoms are in 0.0156 mol of Cs?
0.0156 moles x 6.02x10^23 atoms/mole = 9.39x10^21 atoms
