Avagadro's number says there are 6.02x1023 particles of a pure substance in one mole of that pure substance. (A particle is an atom, molecule, or ion.)
(2.1 mol CO2) (6.02x1023 molecules CO2/1 mol CO2)
= (2.1)( 6.02x1023 molecules CO2) = 1.26 x 1024 molecules CO2
The formula is CO2, so there is one atom of carbon and two atoms of oxygen in each molecule.So there are 2.5x10^21 atoms of carbon in that many molecules of CO2.
To determine the mass of 21 mol of nitrogen (N), you need to know the molar mass of nitrogen, which is approximately 14.01 g/mol. Mass = Number of moles * Molar mass Mass = 21 mol * 14.01 g/mol = 294.21 g Therefore, the mass of 21 mol of nitrogen is approximately 294.21 grams.
There are approximately 5.84 x 10^21 carbon atoms in 9.7 x 10^-3 mol of carbon. This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles of carbon given.
molar mass NH3 = 17 g/molmolar mass SF6 = 146 g/molmolecules in 0.55g SF6 = 0.55g x 1mol/146g x 6.02x10^23 molecules/mole = 2.27x10^21 moleculesgrams NH3 needed = 2.27x10^21 molecules x 1mol/6.02x10^23 molecules x 17g/mol = 0.064 grams
To calculate the number of moles of carbon in a 100g sample, you need to know the molar mass of carbon. The molar mass of carbon is 12 g/mol. Therefore, in a 100g sample, there would be 100g / 12 g/mol = 8.33 moles of carbon.
We know for every 6.022 x 10^23 molecules, we have a mole of a substance, right? So if we have 3920molecules, we can use the above conversion factor to get: 3920 molecules CO2 x (1mol CO2/(6.022x10^23molecules CO2)) = 6.51 x 10^-21 moles CO2. There are three significant figures in this problem, from the 3929 molecules.
Use Avagadro's Number (NA) ... 6.02 X 10^23 atoms (molecules) per mole. so ... 4830 / 6.02 X 10E23 = a really small number Molar equivalent, which my office calculator won't handle. Dude, if you're doing Chemistry homework, you should know this.
The mass of the Earth's atmosphere is 5.25x10^21 grams. If we assume the molar mass of air is approximately 29 grams per mole we get:(5.25x10^21) multiplied by Avogadro's constant (6.02x10^23) and then divided by (29 grams/ mol) = 1.09x10^44 molecules of air in the atmosphere.
There are approximately 1.8 x 10^22 molecules in 0.03 mol of carbon dioxide. This is calculated by multiplying Avogadro's number (6.02 x 10^23) by the number of moles.
The formula is CO2, so there is one atom of carbon and two atoms of oxygen in each molecule.So there are 2.5x10^21 atoms of carbon in that many molecules of CO2.
(6.022*10^23) * [1.000 (g) / (8 * 32.00 (g/mol)] = 2.352*10^21 molecules
0.2550 g AlC3 (1 mol/132 g) =0.001932 mol AlCl3 0.001932 mol AlCl3 (6.022 x 10^23 molecules AlCl3/1 mol AlCl3) = 1.163 x 10^21 1.163x10^21 molecules AlCl3 (3 mol Cl/1 mol AlCl3) =3.490x10^21 Cl ions 3.490x10^21 Cl ions (1 mol/6.022 x 10^23) =5.795x10^-3 moles Cl The formula to solve this problem appears above.
To find the number of molecules in 0.325 g of aspirin, first calculate the number of moles: 0.325 g / 180.2 g/mol = 0.0018 moles. To find the number of molecules, use Avogadro's number (6.022 x 10^23 molecules/mol): 0.0018 moles x 6.022 x 10^23 molecules/mol = 1.0876 x 10^21 molecules.
To calculate the mass of 3.97x10^21 molecules of dinitrogen tetraoxide, you first need to find the molar mass of dinitrogen tetraoxide (N2O4), which is about 92.02 g/mol. Then you can use Avogadro's number (6.022x10^23 molecules/mol) to convert molecules to moles and then multiply by the molar mass to find the mass.
In one (1) molecule CO2 there are 3 atoms ( 1 C-atom and 2 O-atoms), so in 5 molecules CO2 (5CO2) there are 5 x 3 (= 15) atoms. Thus fifteenis the answer to you.
Air is 21% oxygen so 21% of 200 is 42 oxygen molecules.
First, calculate the molar mass of O2 (molecular weight = 32 g/mol). Then, convert the given number of molecules to moles using Avogadro's number (6.022 x 10^23 molecules/mol). The result would be approximately 0.067 moles of O2.