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32 g SO2 x 1 mole SO2/96 g x 6.02x10^23 molecules/mole = 2.0x10^23 molecules
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How do I calculate the quantity of oxygen that contains same number of molecules as 36 grams of water?
36 g water contain 32 g oxygen.32 g oxygen is equivalent to 1 mol oxygen.1 mol has 6,023.10e23 molecules (or atoms, ions).
How many sulfur molecules are in sodium sulfide?
We refer to "molecules" of sodium sulfate as formula units. The formula is Na2SO4. The molar mass is 142 g/mole. And sulfur (S) is 32 out of the entire 142 g. So, percent sulfur is 32/142 (x100%) = 22.5%
What is the equilibrium constant for the reaction SO2 plus NO2--SO3 plus NO?
SO2(g) + NO2(g) ==> SO3(g) + NO(g)Keq = [SO3][NO]/[SO2][NO2] Without knowing concentrations, one cannot calculate the actual value of Keq.
How would the equilibrium change if SO3 were added to SO2(g) plus NO2(g) NO(g) plus SO3(g) plus heat?
The amount of NO and SO3 would increased.
What is the mass (in grams) of 9.18 1024 molecules of methanol (CH3OH)?
9.18x10^24 molecules CH3OH x 1 mole/6.02x10^23 molecules x 32 g/mole = 488 g (to 3 sig figs)
How many molecules of sulfur dioxide are present in 72 g of the substance?
72 grams SO2 (1 mole SO2/64.07 grams)(6.022 X 1023/1 mole SO2) = 6.8 X 1023 molecules of sulfur dioxide ============================
What is the total mass and grams of 0.75 mole of SO2?
The molecular mass of SO2 = 32 + 2(16) = 64. Then 64 g * 0.75 = 48 g.
What is the mass of 0.75 mole of so2?
The molecular mass of SO2 = 32 + 2(16) = 64. Then 64 g * 0.75 = 48 g.
What is the number of molecules in 8 g of oxygen gas?
1) 7 g co 2)16 g so2 3)11 g co2
What is the equilibrium constant for the reaction so2 (g) no2 (g) so3 (g) no (g)?
SO2(g) + NO2(g) ==> SO3(g) + NO(g)Keq = [SO3][NO]/[SO2][NO2] Without knowing concentrations, one cannot calculate the actual value of Keq.
How many grams are in 0.400 mole of SO2?
25.6 g
How many moles of SO2 are present in 250.0 g?
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
How many moles are present in 2.56g of So2?
#1 Remember the moles equation , which is moles = mass(g) /Mr #2 Mr is the relative molecular mass of the given substance. For SO2 it is' 1 x s = 1 x 32 = 32 2 O = 2 x 16 = 32 32 + 32 = 64 Hence substituting moles(SO2) = 2.56g / 64 = moles = 0.04 moles NB When writing chemical formula, single letter symbols are ALWAYS a CAPITAL letter. Hence sulphur is 'S' and oxygen is 'O'. NOT 'o' A double letter symbol is written as , 1st leter is a capital letter and the second letter is small / lower case. e.g. Sodium is 'Na'.
What is the equilibrium constant for the reaction SO2(g) plus NO2(g) --- SO3(g) plus NO(g)?
SO2(g) + NO2(g) ==> SO3(g) + NO(g)Keq = [SO3][NO]/[SO2][NO2] Without knowing concentrations, one cannot calculate the actual value of Keq.
What is the equilibrium constant for the reaction SO2(g) plus NO2(g) SO3(g) plus NO(g)?
SO2(g) + NO2(g) ==> SO3(g) + NO(g)Keq = [SO3][NO]/[SO2][NO2] Without knowing concentrations, one cannot calculate the actual value of Keq.
How do I calculate the quantity of oxygen that contains same number of molecules as 36 grams of water?
36 g water contain 32 g oxygen.32 g oxygen is equivalent to 1 mol oxygen.1 mol has 6,023.10e23 molecules (or atoms, ions).
How many sulfur molecules are in sodium sulfide?
We refer to "molecules" of sodium sulfate as formula units. The formula is Na2SO4. The molar mass is 142 g/mole. And sulfur (S) is 32 out of the entire 142 g. So, percent sulfur is 32/142 (x100%) = 22.5%
