0.943 moles H2O (6.022 X 1023/1 mole H2O)
= 5.68 X 1023 molecules of water
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The value is 1,328.10e-3 moles.
1 mole H2O = 6.022 x 1023 molecules H2O 2mol H2O x 6.022 x 1023 molecules H2O/1mol H2O = 1 x 1024 molecules H2O
Divide mass of 27 g H2O by its molar mass of 18.0 g.mol−1 H2O and you get the number of moles: 1.5 mole H2O
There are 1.5 moles water in 27 grams
A single mole of any substance contains 6.023 E23 instances of that substance. 3.5 moles contains 2.11 E24 molecules of water.
The value is 1,328.10e-3 moles.
6,022140857.1023 molecules---------------------------------------------1 mole2.1022 molecules--------------------------------------------------------------x molex = 0,033 moles
1 mole H2O = 6.022 x 1023 molecules H2O 2mol H2O x 6.022 x 1023 molecules H2O/1mol H2O = 1 x 1024 molecules H2O
Divide mass of 27 g H2O by its molar mass of 18.0 g.mol−1 H2O and you get the number of moles: 1.5 mole H2O
There are 1.5 moles water in 27 grams
A single mole of any substance contains 6.023 E23 instances of that substance. 3.5 moles contains 2.11 E24 molecules of water.
For this you need the atomic (molecular) mass of H2O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. H2O=18.0 grams235 grams H2O / (18.0 grams) = 13.1 moles H2O
Well if one mole of water = 2 moles of hydrogen and 1 mole of oxygen, than 2moles of water = 4 moles of hydrogen and 2moles of oxygen.
The answer is 8,33 moles.
The answer is 0,44 moles.
45 grams H20 x (1 mole H20/18 grams H2O) x (6.02E23 molecules H20/1 mole H2O) the grams H2O and moles H2O cancel out. When you punch it into your calculator, the answer comes out to: =1.505E24 molecules H2O
2.5 moles H2O (2 moles H/1 mole H2O) = 5 moles of hydrogen