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How many molecules of bromine are present in 120 grams of bromine gas?
Wiki User
∙ 11y ago
904,000,000,000,000,000,000,000 (9.04 X 10^23) Bromine atoms.
Wiki User
∙ 11y ago
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How many moles of bromine are in 2.60100 grams of bromine?
.0326 moles
How many moles of bromine gas are in 37.7 grams?
.467 mol of Bromine gas
How many grams in 10 ml of bromine?
31.028g
How many grams are in one mole of Bromine trifluoride?
137g
How many atoms of bromine will you multiply to get moles of bromine?
One mole of Br2 has 6.023 x 1023 bromine molecules or 2 x 6.023 x 1023 bromine atoms.
How many molecules are present in 691 grams of potassium carbonate?
30.115*10^23 molecules
How many molecules are in 46.7 grams of bromine?
Elemental Bromine exists as a diatomic molecule, its atomic number is 35 and its atomic weight is 79.904. A molecule would therefore have a weight of 159.808.A Mole is defined as the amount of any substance that contains as many elementary entities (in this case diatomic molecules) as Avogadro's constant ( 602,214,150,000,000,000,000,000).A mole of Bromine would therefore weigh 159.808 grams.Therefore 46.7 grams of Bromine would contain(46.7)/159.808)*602,214,150,000,000,000,000,000Which is 0.292225670804966 * 602,214,150,000,000,000,000,000Which = 175,982,433,951,992,400,000,000 molecules.
How many moles of bromine atoms are in 2.60x102 grams of bromine?
2,60x102 grams of bromine (Br) is equal to 1,627 moles Br2.
How many moles of bromine are in 2.60100 grams of bromine?
.0326 moles
How many moles of bromine gas are in 37.7 grams?
.467 mol of Bromine gas
How many atoms and molecules are present in 64 grams of sulphur?
12.044*10^23 atoms 1.5055*10^23 S8 molecules
How many grams in 10 ml of bromine?
31.028g
How many grams are in one mole of Bromine trifluoride?
137g
How many atoms of bromine will you multiply to get moles of bromine?
One mole of Br2 has 6.023 x 1023 bromine molecules or 2 x 6.023 x 1023 bromine atoms.
How many oxygen atoms are present in 1.659 grams of ozone gas?
1.659 [grams] / 47.998 [grams / mol] * 6.02214179(30)×1023 [molecules / mole] * 3 [atoms / molecule]. A bunch.
How many grams of bromine are required to completely react with 22.1 g of titanium?
319.6 g of bromine ( should work )
How many molecules of carbon monoxide are present in 3.69 grams of this compound?
3.69 grams CO (1mol CO/28.01g CO )(6.022 X 10^23/1mol CO ) = 7.93 X 10^22 molecules
