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CO2 has a molecular weight of 44.01 g/mol, so 924 grams is equivalent to 20.99522835719155 moles.

Avogadro's number gives the number of units in one mole of any substance (defined as its molecular weight in grams), equal to 6.022140857 × 10 to the 23 (Note the units may be electrons, atoms, ions, or molecules, depending on the nature of the substance).

Thus the number of molecules in 924 grams of Carbon Dioxide is = 20.99522835719155 times 6.022140857 × 10 to the 23. = 126.4362224918882 × 10 to the 23

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Q: How many molecules of carbon dioxide are there in 924 grams of this substance?
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How many molecules of carbon dioxide are in 485 grams of carbon dioxide?

By experiment, a gram mole of any substance contains about 6.022 X 1023 molecules of the substance. The gram molecular mass of carbon dioxide, with the formula CO2, is about 44.01. Therefore 485 grams of carbon dioxide contains 485/44.01 or about 11.02 gram molecular masses. The formula for carbon dioxide shows that each molecule contains one carbon atom. Therefore, 11.02 moles of carbon dioxide contains 11.02 X 6.022 X 1023, or about 4.00 X 1024 atoms of carbon, to the justified number of significant digits.


How many molecules of carbon dioxide are there in 1.0 grams of the gas?

The gram molecular mass of carbon dioxide is about 44.01 grams. By definition, this value is the number of grams of carbon dioxide that contains Avogadro's Number ("AN") of molecules. Avogadro's Number is about 6.022 X 10^23. Therefore the number of molecules in 1 gram is (1/44.01)(AN) or 2 X 10^21 molecules, to the justified number of significant digits.


How many moles of carbon dioxide are there in 19 grams of carbon dioxide?

Moles of carbon dioxide = grams/amu of carbon dioxide. Moles = 19g/44amu Moles of carbon dioxide = .432


How many molecules of sulfur dioxide are present in 72 g of the substance?

72 grams SO2 (1 mole SO2/64.07 grams)(6.022 X 1023/1 mole SO2) = 6.8 X 1023 molecules of sulfur dioxide ============================


The are 6 grams of carbon and 20 grams of oxygen if 22 grams of carbon dioxide are produced and all the carbon is used how many grams of oxygen are left?

22 grams carbon dioxide (0.5 moles)


How much carbon can 22 grams of carbon dioxide make?

6 grams


If you start with 45 grams of ethylene how many grams of carbon dioxide will be produced?

The mass of carbon dioxide is 141,2 g.


How do you measure form grams to atoms?

It depends on the substance. If you have for example, 12 grams of Carbon-12. Then you have 1 mole of carbon 12 which is 6.02 * 1023 molecules of the element, which is equal to 12 grams. One mole of a compound or element is equal to that element's atomic mass in grams.


When there are 3 grams of carbon and 8 grams of oxygen if all of the carbon and oxygen reacted how many grams of carbon dioxide are produced?

11 grams because all is reacted and there is no reactant left over, although if there were only 3 grams of carbon there would have to be 6 grams of oxygen for this to be viable as carbon dioxide is CO2 so the question asked was itself wrong.


How many moles of carbon are there from the original sample of 11.0 grams of carbon dioxide and 4.50 grams of water with a combustion of 7.50 grams?

Look up the molecular weight of carbon dioxide in the periodic table. The formula for carbon dioxide is CO2, which means one atom of carbon and two atoms or oxygen per molecule of carbon dioxide. Carbon has molecular weight of 12. Oxygen molecular weight is 16. Total 12+16+16= 44 11 grams/44 grams/mole=0.25 moles of carbon The grams of water and combustion of 7.5 grams are totally irrelevant. They are only given to possibly confuse you.


Does 10 grams of hydrogen have the same pressure of 10 grams of carbon dioxide?

no


What is the mass of 1 mole of carbon monoxide?

One mole of 12C has a mass of 12.00000 grams (exactly, by definition).One mole of 13C has a mass of 13.00335 grams.One mole of 14C has a mass of 14.00324 grams.One mole of natural carbon - i.e. a sample with the ration of isotopes equal to that in nature - has a mass of 12.0107 grams.