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This molarity is 1,59.
10 moles LiBr (6.022 X 1023/1 mole LiBr)= 6.022 X 1024 atoms of lithium bromide=========================
Molarity is moles per litre. You need to multiply moles per 0.5 litres by 2. Doing this gives you 2.2 moles per litre, i.e. 2.2 molar.
To find the molarity of the substance, divide the moles of the substance by the volume of the solution in liters. First, calculate the moles of magnesium bromide: Convert grams to moles by dividing the given mass by the molar mass of magnesium bromide (184.1 g/mol). Moles of magnesium bromide = 4.13 g / 184.1 g/mol = 0.0224 mol. Next, divide the moles by the volume of the solution in liters: Molarity = 0.0224 mol / 845 L ≈ 0.00003 M (rounded to 3 significant figures).
If you think to a simple binary bromide as NaBr: 166,57.10e23 atoms.
1.25 moles of Lithium Chloride
3 x 0.2 = 0.6 moles
31 grams HCl (1mol/36.458g ) = 0.850 moles 500cm^3 = 0.50 Liters Molarity = moles of solute/liters of solution Molarity = 0.850mol/0.50L = 1.7 Molarity
2LiBr(aq) + Cl2(g) = 2LiCl(aq) + Br2(l) will result in .167 moles of lithium chloride.
This molarity is 1,59.
Molarity is moles of solvent divided by liters of solution, so 6.42 / 1.75 = 3.67M.
FeBr3 (Iron III Bromide) has three moles of bromide for every mole of iron. FeBr2 (Iron II Bromide) has two moles of bromide ion per mole of Iron.
10 moles LiBr (6.022 X 1023/1 mole LiBr)= 6.022 X 1024 atoms of lithium bromide=========================
500ml = 500cm3 = 0.5dm3 0.250M = 0.250mol/dm3 number of moles = molarity x volume number of moles = 0.250mol/dm3 x 0.5dm3 = 0.125mol 0.125mol of NaCl is needed to prepare the required solution.
Molarity = moles of solute/Liters of solution ( 25 ml = 0.025 Liters ) 1.5 M KBr = moles KBr/0.025 Liters = 0.038 moles potassium bromide ------------------
Molarity is moles per litre. You need to multiply moles per 0.5 litres by 2. Doing this gives you 2.2 moles per litre, i.e. 2.2 molar.
Need moles sodium bromide first. 18.7 grams NaBr (1 mole NaBr/102.89 grams) = 0.1817 moles NaBr =====================Now, Molarity = moles of solute/Liters of solution 0.256 M NaBr = 0.1817 moles NaBr/X Liters Liters = 0.1817/0.256 = 0.7098 Liters -------------------------( you do sigi figis )