55.8 moles
23 grams iron ( 1mole Fe/55.85 grams) = 0.41 moles of iron
233,2 g iron Feis equivalent to 4,176 moles.
55.8 moles
100 grams oxygen (1 mole O/16 grams)(2 mole Fe/3 mole O) = 4.17 moles iron --------------------------
55.8 moles
23 grams iron ( 1mole Fe/55.85 grams) = 0.41 moles of iron
Approx 3.997 moles.
4 moles - APEX
233,2 g iron Feis equivalent to 4,176 moles.
55.8 moles
388.grams Fe divided by mass of Fe 388.2g/55.85= 6.95moles of Fe
Balanced equation. 2Fe + 3Br2 -> 2FeBr3 need limiting reactant; suspect iron 9.20 mole Fe (3 mole Br2/2 mole Fe) = 13.8 moles the stated iron moles are not nearly this much; iron limits and drives the reaction looks one to one, so................ 9.20 moles Fe (2 moles FeBr3/ 2mole Fe) = 9.20 moles FeBr3 produced
9 moles of Fe(No3)
To determine the number of moles of Fe that can be made from 25 moles of Fe2O3, you need to write the balanced chemical equation for producing O2 from Fe2O3. 2Fe2O3 = 4Fe + 3O2, which means that 2 moles of Fe2O3 will produce 4 moles of Fe and 3 moles of O2 . Set up a proportion. 3 moles of O2 ÷ 2 moles of Fe2O3 = x moles of O2 ÷ 25 moles of Fe2O3 Cross multiply and divide. 3 moles of O2 * 25 moles of Fe2O3 ÷ 2 moles of Fe2O3 = 37.5 moles of O2 produced.
1 mole of atoms of any element is 6.022 x 1023 atoms. 1 mole of Fe = 6.022 x 1023 atoms Fe 5.98 x 1024 atoms Fe x (1mol Fe/6.022x1023 atoms Fe) = 9.93 moles Fe
1,495