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Moles = weight (in g) / molecular weight = 0.289 / 16 = 0.0180 moles.
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How many moles of methane are there in 8.02 g of methane?
8.02 / 16.04 = 0.5 moles
If in the previous problem only 25.9 grams of water vapor were formed how much methane actually reacted with oxygen?
Methane and oxygen react according to the equation:CH4 + 2O2 -->CO2 + 2H2O Thus 1 mole of methane produces 2 moles of water. 25.9 g of water is 25.9/18 moles = 1.44 moles.So we must have started with 0.72 moles of methane, which is 0.72 x 16 g= 11.51 g of methane.
How many moles of carbon dioxide are produced from the complete combustion of 100.0 grams of methane?
First a balanced chemical equation is needed.CH4 + 2O2 -> CO2 + 2H2OThere is a 1:1 ratio of moles between methane and carbon dioxide so the amount of moles of methane used is the exact number of moles of carbon dioxide yielded.To determine the number of moles of methane we take the amount used and divide by methane's mass which is about 16.04 g/mol.100g/ 16.04g/mol=6.234moles of methane.6.234 moles of methane are used and 6.234 moles of carbon dioxide are produced.
The formula for methane is CH4. Four moles of methane would have a mass of how many grams?
Taking carbon @ 12.01 g/mol & hydrogen @ 1.01 g/ mol methane has 1 carbon & 4 hydrogen, so it is:12.01g + 4(1.01g) = 16.05g per mole.For 4 moles: 4 x 16.05 g = 64.20 g
How many liters of oxygen are needed to exactly react with 27.8 g of methane at STP?
1) First find the number of moles of methane in 27.8 g using the molar mass.See the Related Question to the left of this answer "How do you convert from grams to moles and also from moles to grams?" to do that.2) Then write the balanced reaction. Methane (CH4) reacts with oxygen (O2) to form carbon dioxide (CO2) and water (H2O). See the related question "How do you balance a chemical reaction?" to do that.3) That will tell you the ratio of moles of methane to moles of oxygen (it will be 2 to 1). So from Part 1, multiply the number of moles of methane by 2 to get moles of oxygen. Then, use the Ideal Gas Law to find out how many liters that will take up at STP. Use the Related Question link "How do you solve Ideal Gas Law problems?" to do that.
How many moles of methane are there in 8.02 g of methane?
8.02 / 16.04 = 0.5 moles
If in the previous problem only 25.9 grams of water vapor were formed how much methane actually reacted with oxygen?
Methane and oxygen react according to the equation:CH4 + 2O2 -->CO2 + 2H2O Thus 1 mole of methane produces 2 moles of water. 25.9 g of water is 25.9/18 moles = 1.44 moles.So we must have started with 0.72 moles of methane, which is 0.72 x 16 g= 11.51 g of methane.
How many moles of carbon dioxide are produced from the complete combustion of 100.0 grams of methane?
First a balanced chemical equation is needed.CH4 + 2O2 -> CO2 + 2H2OThere is a 1:1 ratio of moles between methane and carbon dioxide so the amount of moles of methane used is the exact number of moles of carbon dioxide yielded.To determine the number of moles of methane we take the amount used and divide by methane's mass which is about 16.04 g/mol.100g/ 16.04g/mol=6.234moles of methane.6.234 moles of methane are used and 6.234 moles of carbon dioxide are produced.
The formula for methane is CH4. Four moles of methane would have a mass of how many grams?
Taking carbon @ 12.01 g/mol & hydrogen @ 1.01 g/ mol methane has 1 carbon & 4 hydrogen, so it is:12.01g + 4(1.01g) = 16.05g per mole.For 4 moles: 4 x 16.05 g = 64.20 g
How many liters of oxygen are needed to exactly react with 27.8 g of methane at STP?
1) First find the number of moles of methane in 27.8 g using the molar mass.See the Related Question to the left of this answer "How do you convert from grams to moles and also from moles to grams?" to do that.2) Then write the balanced reaction. Methane (CH4) reacts with oxygen (O2) to form carbon dioxide (CO2) and water (H2O). See the related question "How do you balance a chemical reaction?" to do that.3) That will tell you the ratio of moles of methane to moles of oxygen (it will be 2 to 1). So from Part 1, multiply the number of moles of methane by 2 to get moles of oxygen. Then, use the Ideal Gas Law to find out how many liters that will take up at STP. Use the Related Question link "How do you solve Ideal Gas Law problems?" to do that.
How many moles does 3.80 g Zn have?
3,80 g Zn have 0,058 moles.
If you have g of beryllium how many moles is this equivalent to?
The formula is: number of moles = g Be/9,012.
How many moles of argon are in 24.7 g of argon?
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
What are the steps needed to convert 77.2 grams of methane to molecules of methane. Please wrote them out ( indluding tchart)?
Step1: Find molar mass of methane, CH4. C=12; H=1; 12+1+1+1+1 = 16 g/moleStep2: Convert grams to moles. 77.2 g x 1 mole/16 g = 4.825 moles methaneStep3: Convert moles to molecules using Avogadro's number.4.825 moles x 6.02x10^23 molecules/mole = 2.90x10^24 moleculesUnfortunately, I don't know what a tchart is, so I didn't include it.
How many moles are in 23.34 g of NaCl?
The answer is 0,4 moles.
How many moles of CCl4 are there in 56 g?
The answer is 0,364 moles.
How many moles are in 19.2 g of CS2?
The answer is 0,253 moles.
