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0.377 grams of Kr is equal to 0,0045 moles.
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How many grams are contained in 4.56 moles of krypton Kr?
4.56 moles Kr x 83.798 g/mole = 382.119 grams = 382 grams (to 3 significant figures)NOTE: You should not use more than 3 significant figures since 4.56 moles limits the precision. Thus the answers of 381.66g and 382.1188 g are incorrect.
What mass in g does 3.99 moles of Kr have?
3,99 moles of Kr have 334,35 g.
What mass in g 3.99 moles of Kr have?
3,99 moles of Kr is equal to 334,354 g.
How many moles are in 1.7 times 10 to the 25th power atoms of krypton?
1 mole Kr = 6.022 x 1023 atoms 1.7 x 1025 Kr atoms x (1 mole Kr)/(6.022 x 1023 Kr atoms) = 28 moles Kr (rounded to two sig figs)
How do you convert 1.29 mol Kr to a number of atoms?
Just multiply the moles of Kr by Avogadro's number. Formal set up.1.29 moles Kr (6.022 X 1023/1 mole Kr)= 7.77 X 1023 atoms of krypton====================
What mass does 3.99 moles of Kr have?
3.99 moles × 83.8 grams/mol = 334.362 grams
How many grams are contained in 4.56 moles of krypton Kr?
4.56 moles Kr x 83.798 g/mole = 382.119 grams = 382 grams (to 3 significant figures)NOTE: You should not use more than 3 significant figures since 4.56 moles limits the precision. Thus the answers of 381.66g and 382.1188 g are incorrect.
How many moles of Kr are contained in 398 mg of Kr?
The mass of 1 mole of an element is its atomic weight on the periodic table in grams.1g = 1000mgThe mass of 1 mole of Kr = 83.80g KrConvert mg Kr to g Kr.398mg Kr x (1g/1000mg) = 0.398g KrConvert g Kr to mol Kr.0.398g Kr x (1mol Kr/83.80g Kr) = 4.75x10-3mol Kr
What mass in g does 7.98 moles of Kr have?
7.98 moles of Kr have 668,708 g.
What mass (in g) does 7.98 moles of Kr have?
7.98 moles of Kr have 668,708 g.
What mass in g does 3.99 moles of Kr have?
3,99 moles of Kr have 334,35 g.
What mass in g 3.99 moles of Kr have?
3,99 moles of Kr is equal to 334,354 g.
What volume will 0.405 g of krypton gas occupy at STP?
First we need the moles of krypton gas. Monoatomic gas.0.405 grams Kr (1 mole Kr/83.80 grams)= 0.004833 moles krypton gas======================Now the ideal gas equation.PV = nRT(1 atm)(X volume) = (0.004833 moles Kr)(0.08206 L*atm/mol*K)(298.15 K)= 0.118 Liters of krypton gas--------------------------------------
How many Kr atoms are there in 2.51 moles of Kr?
The number of atoms is 15,11.10EX23.
How many moles are in 1.7 times 10 to the 25th power atoms of krypton?
1 mole Kr = 6.022 x 1023 atoms 1.7 x 1025 Kr atoms x (1 mole Kr)/(6.022 x 1023 Kr atoms) = 28 moles Kr (rounded to two sig figs)
How do you convert 1.29 mol Kr to a number of atoms?
Just multiply the moles of Kr by Avogadro's number. Formal set up.1.29 moles Kr (6.022 X 1023/1 mole Kr)= 7.77 X 1023 atoms of krypton====================
How many moles F2 are required to produce 3.0 moles KrF6 in the equation Kr plus 3F2 producing KrF6?
Given the balanced equation Kr + 3F2 --> KrF6 In order to find how many moles of F2 are needed to produce 3.0 moles of KrF6, we must convert from moles to moles (mol --> mol conversion). 3.0 mol KrF6 * 3 molecules F2 = 9.0 mol F2 --------- 1 molecule F2
