Molecular weight of potassium (K): 39.1 g/mole...Just divide 156 by the molecular weight to get moles:
156/39.1 = 3.99 moles K
Divide mass by atomic mass:
0.98 (g K) / 39.1 (g/mol K) = 0.020 mol K
Atomic mass of potassium, K = 39.1
Amount of potassium is 156.4g sample = 156.4/39.1 = 4.00mol
There are 4 moles of potassium in 156.4 grams of potassium.
The atomic mass of potassium, K is 39.1.
Amount of potassium = mass of sample / atomic mass= 2.25/39.1 = 0.0575mol
In 48 g of potassium are 1,228 moles.
Atomic mass of potassium = 39.10 g/mole156.4 g x 1 mole/39.10 g = 4.000 moles (to 4 significant figures)
224 g are in two moles of potassium dichromate.
1,5 moles of potassium carbonate have 276,41 g.
This mass is 42,28 g.
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
Potassium (chemical symbol K) has atomic number 39.1. Amount of K in 449g sample = 449/39.1 = 11.5mol There are 11.5 moles of potassium in a 449g sample.
12 g of potassium is equivalent to 0,307 moles.
34,7 moles of potassium 1 356,7 g.
224 g are in two moles of potassium dichromate.
449 g K x 1 mole K/39 g K = 11.5 moles (3 sig figs)
242.594 g
0.4g/mol
449 (g K) / 39.1 (g/mol K) = 11.5 mol K
1,5 moles of potassium carbonate have 276,41 g.
The answer is 224,24 g oxygen.
This mass is 42,28 g.
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
Potassium (chemical symbol K) has atomic number 39.1. Amount of K in 449g sample = 449/39.1 = 11.5mol There are 11.5 moles of potassium in a 449g sample.