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The equivalent of 125 g zinc is 1, 91 moles.
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∙ 8y ago
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How many moles does 3.80 g Zn have?
3,80 g Zn have 0,058 moles.
What is the amount in moles of 3.80g Zn?
The answer is 0,058 moles.
What is the limiting reactant of 0.5 mol of zinc to 0.75 mol of hydrochloric acid?
Balanced equation first.Zn + 2HCl --> ZnCl2 + H20.5 mole Zn (2 moles HCl/1 mole Zn)= 1 mole HCl================you do not have this much moles HCl0.75 moles HCl (1 mole Zn/2 mole HCl)= 0.375 moles Zn===================you have more moles Zn than thisSo. HCl limits this reaction.
What is the number of atoms in 1.88 moles of Zn?
1.88 mol Zn ( 6.022 X10^23/1mol Zn ) = 1.13 X10^24 atoms.
How many milliliters of 0.248M HCl are needed to react with 1.36 grams of zinc to produce hydrogen?
First, write a balanced equation for this reaction. The reactants are HCl and Zn and the products are ZnCl2(aq), and H2(g). For how to write a balanced equation, see the Related Questions to the left. Then, convert the grams of Zn into moles of Zn. To do that, see the Related Questions to the left. Then use stoichiometry to determine how many moles of HCl are necessary to react with that number of moles of Zn. See the Related Questions to the left for how to solve stoichiometry problems. Finally, determine how many milliliters of solution you need to get that many moles of HCl. To do that, use this equation: number of moles = number of liters * molarity
How many moles does 3.80 g Zn have?
3,80 g Zn have 0,058 moles.
How many moles of zinc Zn are in 1.33 1024 Zn atoms?
6,022140857.10e23--------------1 mol1,33.10e24----------------------------xx = 1,33.10e24/6,022140857.10e23 = 2,2 moles Zn
How many moles of HCl are needed to react with 2.3 moles of Zn in the following reaction?
I assume you mean this reaction. Zn + 2HCl --> ZnCl2 + H2 2.3 moles zinc (2 moles HCl/1 mole Zn) = 4.6 moles hydrochloric acid needed ========================
What is the mass in grams of 0.040 moles Zn?
0,040 moles Zn equal 2,614 g.
How many grams are in 671.89 moles of zinc?
For this you need the atomic mass of Zn. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.671.89 moles Zn × (65.4 grams)) = 10.3 grams Zn
How many grams of Zn are in 0.356 moles of zinc?
0,356 moles of zinc contain 23,27 g.
What is the amount in moles of 3.80g Zn?
The answer is 0,058 moles.
What is the limiting reactant of 0.5 mol of zinc to 0.75 mol of hydrochloric acid?
Balanced equation first.Zn + 2HCl --> ZnCl2 + H20.5 mole Zn (2 moles HCl/1 mole Zn)= 1 mole HCl================you do not have this much moles HCl0.75 moles HCl (1 mole Zn/2 mole HCl)= 0.375 moles Zn===================you have more moles Zn than thisSo. HCl limits this reaction.
What is the number of atoms in 1.88 moles of Zn?
1.88 mol Zn ( 6.022 X10^23/1mol Zn ) = 1.13 X10^24 atoms.
How many milliliters of 0.248M HCl are needed to react with 1.36 grams of zinc to produce hydrogen?
First, write a balanced equation for this reaction. The reactants are HCl and Zn and the products are ZnCl2(aq), and H2(g). For how to write a balanced equation, see the Related Questions to the left. Then, convert the grams of Zn into moles of Zn. To do that, see the Related Questions to the left. Then use stoichiometry to determine how many moles of HCl are necessary to react with that number of moles of Zn. See the Related Questions to the left for how to solve stoichiometry problems. Finally, determine how many milliliters of solution you need to get that many moles of HCl. To do that, use this equation: number of moles = number of liters * molarity
When a strip of zinc is placed in a solution of silver nitrate Zn replaces Ag to form zinc nitrate and metallic silver is formed How many moles of silver will be generated if 1 point 30 moles of Zn?
As shown by the ionic equation of the reaction, Zn (s) + 2 Ag+ (aq) --> 2 Ag (s) + Zn2+ (aq), each mole of zinc produces two moles of silver. Therefore, 1.30 moles of zinc will displace 2.60 moles of silver.
How many kilos are there in 125g?
125g = 0.125kg
