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0,040 moles Zn equal 2,614 g.
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∙ 7y ago
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How many grams of Zn are in 0.356 moles of zinc?
0,356 moles of zinc contain 23,27 g.
How many grams of hydrochloric acid are reacted when 1.80 mol of zinc is reacted with 7.10 mol of hydrochloric acid?
A lot of that hydrochloric acrid is excess and some grams will not react, I think. Balanced equation first. Zn + 2HCl -> ZnCl2 + H2 Check to make sure of limiting reactant; I suspect zinc. 1.80 moles Zn (2 mole HCl/1 mole Zn) = 3.60 moles HCl You have a lot more than that, Zn limits and will drive the reaction 1.80 moles Zn (2 moles HCl/1 mole Zn)(36.458 grams/1 mole HCl) = 131 grams of hydrochloric acid reacted with that Zinc amount ----------------------------------------------------------------------------------
How many moles of ZnCl2 will be produced from 23.0 g of Zn?
Atomic mass from my Periodic Table for Zinc is 65.38. This means 1 mole of naturally occurring zinc has a mass of 65.38 grams. If your zinc sample is pure zinc then: (mass of your sample)/(65.38 grams) = # moles of zinc.
How many atoms are in 7.1 mol Zn?
From my understanding as there is only one mole of zinc which means the mass is 65.4 . Then to get the number of particles the answer is simply 1(the number of moles) x 6.02 x 10 ^ 23. is this correct this is not the answer just a further question ...
How many moles of HCl are needed to react with 2.3 moles of Zn in the following reaction?
I assume you mean this reaction. Zn + 2HCl --> ZnCl2 + H2 2.3 moles zinc (2 moles HCl/1 mole Zn) = 4.6 moles hydrochloric acid needed ========================
How many grams are in 671.89 moles of zinc?
For this you need the atomic mass of Zn. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.671.89 moles Zn × (65.4 grams)) = 10.3 grams Zn
How many moles are in 22.5 grams of zinc?
For this you need the atomic mass of Zn. Then take the mass in grams and divide it by the atomic number (multiplied by one mole for units to cancel) to find number of moles. Zinc's atomic mass is 65.4 grams.22.5 g Zn / (65.4 grams) = .344 moles Zn
What is the amount in moles of 3.45 g Zn?
Calculated by dividing mass (in grams) by atomic mass of Zn: 3.45(g) / 65.38(g/mole) = 0.0528 mole
How many grams of Zn are in 0.356 moles of zinc?
0,356 moles of zinc contain 23,27 g.
What is the number of atoms in 1.88 moles of Zn?
1.88 mol Zn ( 6.022 X10^23/1mol Zn ) = 1.13 X10^24 atoms.
How many moles of ZnCl2 will be produced from 28g of Zn assuming CuCl2 is available in excess?
Ok, so we have... Zn + CuCl2 -> ZnCL2 + Cu And we are given that we have 28g of Zn (Zinc). But the question calls for moles of ZnCl2. So, the first step is to convert grams to moles of Zn. We will need to find the AMU (Atomic Mass Units) that a Zn atom's mass. A Zn atom has a mass of 63.546 AMU. Now, we take the given mass and divide it by the mass of the atom to get the moles of reactant we have. 28g/63.546AMU≈ .4406257moles If your teacher/ professor cares about sig figs, then it's .44 because you only have two sig figs from the given from the given mass of Zn (28g). Now, the easy part. What is the ratio of Zn atoms on the reactant side to Zn atoms on the product side? 1:1 And since we have excess CuCl2 Nothing else limits the reaction. So, .44 (or how ever far your teacher wants you to round) moles of Zn reactants in a ideal environment (you will learn later that no reaction is 100% and that there are reactants always left over and how to solve for that) produces .44 moles of ZnCl2.
How many grams of hydrochloric acid are reacted when 1.80 mol of zinc is reacted with 7.10 mol of hydrochloric acid?
A lot of that hydrochloric acrid is excess and some grams will not react, I think. Balanced equation first. Zn + 2HCl -> ZnCl2 + H2 Check to make sure of limiting reactant; I suspect zinc. 1.80 moles Zn (2 mole HCl/1 mole Zn) = 3.60 moles HCl You have a lot more than that, Zn limits and will drive the reaction 1.80 moles Zn (2 moles HCl/1 mole Zn)(36.458 grams/1 mole HCl) = 131 grams of hydrochloric acid reacted with that Zinc amount ----------------------------------------------------------------------------------
How many moles of ZnCl2 will be produced from 23.0 g of Zn?
Atomic mass from my Periodic Table for Zinc is 65.38. This means 1 mole of naturally occurring zinc has a mass of 65.38 grams. If your zinc sample is pure zinc then: (mass of your sample)/(65.38 grams) = # moles of zinc.
How many moles does 3.80 g Zn have?
3,80 g Zn have 0,058 moles.
How many atoms are in 7.1 mol Zn?
From my understanding as there is only one mole of zinc which means the mass is 65.4 . Then to get the number of particles the answer is simply 1(the number of moles) x 6.02 x 10 ^ 23. is this correct this is not the answer just a further question ...
How many moles of zinc Zn are in 1.33 1024 Zn atoms?
6,022140857.10e23--------------1 mol1,33.10e24----------------------------xx = 1,33.10e24/6,022140857.10e23 = 2,2 moles Zn
How many grams of zinc can react with 225ml of 0.200 m HCl solution?
Balanced equation first.Zn + 2HCl - ZnCl2 + H2now we find moles HCl by....Molarity = moles of solute/Liters of solution ( 225 ml = 0.225 Liters )0.200 M HCl = X moles/0.225 Liters= 0.045 moles HCl================Now, drive reaction backwards.0.045 moles HCl (1 mole Zn/2 mole HCl)(65.41 grams/1 mole Zn)= 1.47 grams zinc reacted----------------------------------
