1.5
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To calculate the moles in 11.5 g of C2H5OH (ethanol), you first need to know the molar mass of C2H5OH. This is obtained by adding the mass of the elements: C = 2x12 = 24; H = 6x1 = 6; O = 16.
Thus, 24 + 6+ 16 = 46 g/mole. Then, 11.5 g x 1 mole/46g = 0.25 moles
1 gram of C2H5OH is equivalent to 0,0217 moles.
How many moles are represented by 11.5g of C2H5OH?
1.5 moles
14.7 g
3,80 g Zn have 0,058 moles.
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
The answer is 0,364 moles.
The answer is 0,253 moles.
115/7=16.42mol
The mass of 2 moles of ethyl alcohol would be 92,14 grams.
79c
80c
88c
80c
35 c
80 degrees Celsius
14.7 g
3,80 g Zn have 0,058 moles.
The formula is: number of moles = g Be/9,012.
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles