Cobalt (III) hydroxide's formula is Co(OH)3
MOLES are found by grams you have/ molar mass of the molecule.
To find the molar mass, you must first find the masses of the elements. In Co(OH)3 there are 3 elements: Cobalt (Co), Oxygen (O), and Hydrogen (H)
Cobalt's Atomic Mass is 58.933 (but we'll round that 59)
Oxygen's atomic mass is 15.999 (but we'll round that 16)
Hydrogen's atomic mass is 1.0079 (but we'll just call that 1.)
BUT WAIT. THERE'S MORE.
There is 1 Cobalt atom, so we'll keep 59.
There are THREE Oxygen atoms, so we have to multiply 16 by 3. (That's 48.)
And there are also THREE Hydrogen atoms, so we have to multiply 1 by 3. (That's 3, but I'm sure you knew that.)
So let's add them up: 59 + 48 + 3 = 110 grams.
Almost there!
3.96 /110 = .036 moles.
CHEMisTRY!
Molar mass of Co = 58.933200 g/mol
Remembering that:
m=n * Mr which is mass=number of moles multiplied by molar mass.
So,
m=1*(12.01+16.00)
= 28.01g
Cobalt's atomic mass is about 58.93 (according to the periodic table) so the mass of 1 mole of cobalt atoms will be 58.93 grams.
1 mole Co = 58.93320 grams (atomic weight from Periodic Table in grams)
118g Co x 1mol/58.93320g = 2.00 moles Co
10 grams of cobalt are in 2 moles
yes
The gram atomic/molar mass of cobalt is 63.546. Multiplying this number by 0.0489 yields the answer of 3.11 grams, to the justified number of significant digits.
1 mole Co = 58.933g Co (atomic weight in grams)1 mole Co atoms = 6.022 x 1023 atoms CoConvert grams Co to moles Co.22.6g Co x (1 mole Co/58.933g) Co = 0.383 mole CoConvert mole Co to atoms Co.0.383 mole Co x (6.022 x 1023 atoms Co/1 mole Co) = 2.31 x 1023 atoms Co
Remember the equation Moles = mass(g) / Relative Atomic/molecular mass (Ar/Mr) moles = mass(g) / Ar/Mr The mass is 14 g The Mr for CO is:- From the Periodic Table Mass of C = 12 and mass of O = 16 12 + 16 = 28 Substituting moles(CO = 14g / 28 moles = 0.5 ( or 1/2 mole)
34.5 g CaCO3 (1 mole CaCO3/100.09 g)(1 mole Ca/1 mole CaCO3)(40.08 g/1 mole Ca) = 13.8 grams calcium ===============
C + 1/2 O2 ----> CO ------> mole basis 12 C + 16 O2 ----> 28 CO -----> mass basis CO made = ( 36 g C ) ( 28 g CO / 12 g C ) = 84 g CO <-----------------
Molecular mass of CO = atomic weight of O + atomic weight of C = 28,01 g
The gram atomic/molar mass of cobalt is 63.546. Multiplying this number by 0.0489 yields the answer of 3.11 grams, to the justified number of significant digits.
57 grams Florine (1 mole F/19.00 grams)(6.022 X 10^23/1 mole F) = 1.8066 X 10^24 atoms Florine 1.8066 X 10^24 atoms (1 mole Co/6.022 X 10^23)(58.93 grams/1 mole Co) = 176.79 grams of cobalt ( sigi figi might be 180 grams )
1 mole Co = 58.933g Co (atomic weight in grams)1 mole Co atoms = 6.022 x 1023 atoms CoConvert grams Co to moles Co.22.6g Co x (1 mole Co/58.933g) Co = 0.383 mole CoConvert mole Co to atoms Co.0.383 mole Co x (6.022 x 1023 atoms Co/1 mole Co) = 2.31 x 1023 atoms Co
For this you need the atomic (molecular) mass of CO. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.4.5 grams / 28.0 grams = .161 moles CO
Pure Urea (H2N-CO-NH2) has a mole wt of 60.06. SO ... 60.06 gm is one gm mole.
Remember the equation Moles = mass(g) / Relative Atomic/molecular mass (Ar/Mr) moles = mass(g) / Ar/Mr The mass is 14 g The Mr for CO is:- From the Periodic Table Mass of C = 12 and mass of O = 16 12 + 16 = 28 Substituting moles(CO = 14g / 28 moles = 0.5 ( or 1/2 mole)
5.34 grams W(CO)6 (1 mole W(CO)6/351.86 grams)(6 moles C/1 mole W(CO)6)(6.022 X 1023/1 mole C) = 5.48 X 1022 atoms of carbon ========================
2.75 micrograms? 2.75 ug Co (1 gram/10^6 ug)(1 mole CoC16H2O/1 mole Co)(269.106 grams/1 mole CoC16H2O) = 7.4 X 10^-4 grams * 10^6 = 740 micrograms ----------------------
C = 12O = 16 CO = 28 g for 1 mole
34.5 g CaCO3 (1 mole CaCO3/100.09 g)(1 mole Ca/1 mole CaCO3)(40.08 g/1 mole Ca) = 13.8 grams calcium ===============
To do this, you need to know the molecular weight of the element you're dealing with, by adding up the atomic weights of the elements involved (found on any periodic table). The molecular weight is the mass in grams of the compound in one mole - this will provide you with a conversion factor. So take the measurement in grams and divide it by the molecular weight to convert to moles. Really what you're doing is multiplying the number by 1 mole, and dividing it by the equivalent of one mole, the molecular weight. That's the thought process behind unit analysis and how you get your "units to cancel".In this case, the answer is about 12.33 moles carbon monoxide.