Remember the equation
Moles = mass(g) / Relative Atomic/molecular mass (Ar/Mr)
moles = mass(g) / Ar/Mr
The mass is 14 g
The Mr for CO is:- From the Periodic Table Mass of C = 12 and mass of O =
16
12 + 16 = 28
Substituting
moles(CO = 14g / 28
moles = 0.5 ( or 1/2 mole)
1 mole CO = 28.00101g CO
14g CO x 1mol CO/28.00101g CO = 0.50 mole CO
1,4 moles of CO are produced.
How many moles of atoms are contained in 382 g Co
The answer is 6,482 moles.
no
2,55 moles of the compound CO have 71,4 grams.
1,4 moles of CO are produced.
4,54 L of CO have 0,182 moles.
How many moles of atoms are contained in 382 g Co
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
The answer is 6,482 moles.
382 g Co contain 6,482 moles.
no
CO2 + H2 -> CO + H2O one to one here 30.6 moles H2O (1 mole H2/1 mole H2O) = 30.6 moles Hydrogen gas needed
2,55 moles of the compound CO have 71,4 grams.
There are 6.023x10^23 molecules in one mole of a compound. So now, you have to find how many moles of each compound you have. CO's molecular weight is (12+16) = 28 g/mol N2's molecular weight is (14+14) = 28 g/mol So you find the moles of each. moles of N2 = 20g/ 28g/mol = .714 moles moles of CO = 16g / 28 g/mol = .571 moles So, N2 has (.714 *6.023x10^23) has 4.3 x10^23 molecules and CO (.571 *6.023x10^23) has 3.4x10^23 molecules. So, 20g of N2 has more molecules than 16g of CO
26,3 g cobalt is equivalent to 0,446 moles.
0,83moles glucose are burned.