C + 1/2 O2 ----> CO ------> mole basis
12 C + 16 O2 ----> 28 CO -----> mass basis
CO made = ( 36 g C ) ( 28 g CO / 12 g C ) = 84 g CO <-----------------
It depends on the chemical reaction that is occurring. Can you provide the balanced equation for the reaction so we can calculate the amount of NaCl produced?
If 1 mole of carbon reacts, 1 mole of CO is produced according to the balanced chemical equation for the reaction. Therefore, if 1.4 moles of carbon react, 1.4 moles of CO will be produced.
The reaction between hydrogen and ammonia to form ammonia is 3H2 + N2 → 2NH3. To find the amount of ammonia produced when 6.00g of hydrogen reacts, first convert the mass of hydrogen to moles using its molar mass. Then, use the mole ratio from the balanced equation to find the moles of ammonia produced, and finally, convert this to grams using the molar mass of ammonia.
Fe2O3 (s) + 3 CO (g) 🡪 2 Fe (s) + 3 CO2 (g) Calculate the number of grams of CO that can react with 250 g of Fe2O3. Calculate the number of grams of Fe and the number of grams of CO2 formed when 250 grams of Fe2O3 reacts.
To determine how many moles of aluminum are produced from 33 grams, divide the given mass by the molar mass of aluminum, which is approximately 26.98 g/mol. So, 33 g / 26.98 g/mol ≈ 1.22 moles of aluminum are produced.
360g = 12.7 ounces
75 g sodium chloride contain 29,75 g sodium.
8.20g of carbon monoxide, how many grams of methanol will be produced?
Approximately 240g of hydrogen gas are produced when 120.0g of zinc metal completely reacts with hydrochloric acid.
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
360g is 0.8 (0.793664) pounds.
175 and one half in our last box!
1,4 moles carbon monoxide are produced.
7
11 grams because all is reacted and there is no reactant left over, although if there were only 3 grams of carbon there would have to be 6 grams of oxygen for this to be viable as carbon dioxide is CO2 so the question asked was itself wrong.
The complete question: Lead (II) oxide reacts with ammonia forming solid lead nitrogen gas and liquid water. 1.)How many grams of ammonia are consumed in the reaction of 75.0g lead (II) oxide? 2.) If 56.4g of lead are produced how many grams of nitrogen are also formed?