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1 mol Cr/6.02x10^23 atoms x 3.6x10^24 atoms = 5.98 moles
The answer is 3,587 moles.
2.36 moles x 6.022*10^23 atoms/mole. Moles cancel and you are left with 1.42*10^24 xenon atoms.
Pieces of atoms? 6.01024 atoms of aluminum (1 mole Al/6.022 X 10^23) = 9.98047 X 10^-24 moles of aluminum ---------------------------------------------------
4.2 X 10^24 atoms of gold / 6.022 X 10^23 atoms per mol) = 7.0 moles of gold
1 mol Cr/6.02x10^23 atoms x 3.6x10^24 atoms = 5.98 moles
The answer is 3,587 moles.
In a mole there is 6.022 x 1023 atoms. In two moles there are twice that amount.
2.36 moles x 6.022*10^23 atoms/mole. Moles cancel and you are left with 1.42*10^24 xenon atoms.
12.044x10^[24] atoms
2.09 moles Sn (6.022 X 10^23 atoms / 1 mole Sn) = 1.26 X 10^24 atoms of tin
10 moles of oxygen atoms or 5 moles of oxygen molecules.
If you meant 8.9 * 10^24, then there are 14.78 moles. 8.9 e24 (# of atoms) / 6.02 e23 (# of atoms in a mole) = 14.78 (# of moles)
Pieces of atoms? 6.01024 atoms of aluminum (1 mole Al/6.022 X 10^23) = 9.98047 X 10^-24 moles of aluminum ---------------------------------------------------
4.2 X 10^24 atoms of gold / 6.022 X 10^23 atoms per mol) = 7.0 moles of gold
The number of atoms is 15,11.10EX23.
3 moles of Ca would have 1.806 × 10^24 atoms.