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1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
4,5.10e28 molecules of sodium fluoride NaF are equal to 0,745.10e5 moles.
3.6 moles N2SO4 (142.05 grams/1 mole Na2SO4) = 511.38 grams Na2SO4 ==================( you do significant figures )
No amount of sodium sulphate can be formed from sodium hydroxide alone, because sodium sulfate contains sulfur and sodium hydroxide does not. By neutralization with sulphuric acid, one formula unit of sodium sulphate can be formed from two moles of sodium hydroxide, according to the equation 2 NaOH + H2SO4 -> Na2SO4 + 2 H2O.
The answer is 0,111 moles.
1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
Hahaha
4,5.10e28 molecules of sodium fluoride NaF are equal to 0,745.10e5 moles.
2
alot
The answer is approx. 2 moles (for anhydrous sodium sulfate).
4.5 moles
The reaction requires 2 moles of hydrogen gas and 1 mole of oxygen gas to produce 2 moles of water.
The answer is 10 moles water.
The answer is 10 moles water.
10 moles of water are released.
4.06 X 1025 molecules NaF (1 mole NaF/6.022 X 1023) = 67.4 moles sodium fluoride =====================