50 mg is .05 gm
THE MEANING OF % IS 1 gm of substance in 100 mL of solvent.(w/v) so you can prepare 1 % sodium citrate by dissolving 1.0 g of Sodium citrate in to 100 ml of water.
31.1 gm
28.35 gm in 1 ounce. So 550 gm is 19.4 ounces
190mmh x510mm
C2H4O2 + NaOH = H2O + C2H3O2Na Acetic acid (60 gm) + sodium hydroxide ( 40 gm) = 100 gm water (18 gm) + sodium acetate (82 gm) = 100 gm Ratio reactants to products = 1:1 Molarity = moles / L, 3M = 3 moles / 1 L Acetic acid = 60 gm / total reactant 100gm = 1.8 moles Multiply by 3 = 1.8 moles or 180 grams Sodium Hydroxide = 40 gm / total reactant 100 mg = 1.2 moles or 120 grams. 180 grams acetic acid + 120 grams sodium hydroxide = 300 grams. 300 grams divided by 1 liter = 3M So in order to make 3 M sodium acetate combine solution, add 180 grams acetic acid and 120 grams sodium hydroxide with 1 liter of water.
9.991 Moles (water) 8.982 Moles (heavy water)
456 gm
1 mole.
Barium (Ba) has an At. No. of 56, and an At. Wt. of 137.36.(7.8 gm moles) X (137.36 gm/gm mole) = 1071.408 gm.
The atomic weight of magnesium is 24.31; therefore, the number of moles in 100 gm is 100/24.31 = 4.11, to the justified number of significant digits.
It will be 11.5 gm od Na metal
molar weight of N = 14 grams/mole 35.7 grams/14 grams/mole = 2.55 moles
According to wikipedia the density of sodium is 0.968 gm.cm-3. This is a mass of 0.160 gm. Then this much sodium would occupy 0.160 gm / ( 0.968 gm.cm-3 ) = 0.165 cm3.
4.50 moles NO2 X (46 grams NO2) / (1 mole NO2) x (4 moles NO2) / (7 moles O2) x (1 mole O2) / (32 gm O2) = 3.70 grams O2
50 mg is .05 gm
1 ppm means 1 mg/l so 1000 ppm means 1000 mg/l or 1gm/l , FW of sodium arsenite NaAsO2 is 130 ans As is 75 75 gm of arsenite is present in 130 gm sodium arsenite 1 gm---------------will be---------130/75= 1.73 gm so if 1.73 gm of sodium arsenite is present in 1 litre of water it makes 1000 ppm solution of arsenite