divide the mass by molar mass. Molar mass of NH3 is 17. answer is 0.044mol
Molar mass of ammonia is 17 g. Hence 0.75 g of ammonia will contain 0.044 moles of ammonia.
Molar mass of ammonia is 17 g. Therefore in 12 x 10.3 g of ammonia there will be 7.27 moles of ammonia.
Ammonia is NH3 (not NH2) so its molar mass is 17 g/mol. In 1.2*10^3 g there are1.2*10^3(g) / 17 (g/mol) = (70.6 =) 71 mol NH3.
This is a chemical calculation. there are 0.04166 moles in it.
The number of ammonia molecules is 59 720.10e23.
2.3L / 22.4 liters per mole = approx. 0.1 moles.
Molar mass of ammonia is 17 g. Therefore in 12 x 10.3 g of ammonia there will be 7.27 moles of ammonia.
1 g of ammonia (NH3) is equal to 0,059 mol.
Ammonia is NH3 (not NH2) so its molar mass is 17 g/mol. In 1.2*10^3 g there are1.2*10^3(g) / 17 (g/mol) = (70.6 =) 71 mol NH3.
This is a chemical calculation. there are 0.04166 moles in it.
Ammonia = NH3Molecular mass = 16.0Formula of grams to moles: grams / molecular mass = moles170,000 g / (16.0) = 10,600 moles NH3Note that the answer is with three significant digits
The mass of ammonia will be 95,03 g.
5.8 x 10-2 mol
The mass of 3 mol of ammonia is 51,093 g; the number of ammonia molecules in 3 moles is18,066422571.10e23.
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
26.9 - 27.4
2 mol H2 x 2 mol H2O/2 mol H2 x 18 g H2O/1 mol H2O = 36 g H2O
The number of ammonia molecules is 59 720.10e23.