2.3L / 22.4 liters per mole = approx. 0.1 moles.
The molar mass of ammonia is 17,031 g.
The density of ammonia is 0,769 g/L.
The mass of 2,3 L is 1,7687 g.
1,7687 g is equivalent to 0,104 moles.
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
0.67 mol
NH3 is not liquid but gas at STP. It is however very well soluble in water, solution called ammonia.
Approx 0.223 moles.
1 mole of gas = 22.7 litre ( at STP) 22.7 Litre of gas = 1 mole 1 litre of gas = 2.27 litre of gas = mole www.examville.com
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
0.67 mol
Assuming that this ammonia gas is at STP, you can use Avogadro's number to gind the number of moles of gas:(387 x 1021 molecules) x (1 mol / 6.02x1023particles) x (17.03 g / 1 mol) =110 g NH3
8,4 liters of nitrous oxide at STP contain 2,65 moles.
16,8 L of Xe gas at STP is equivalent to 0,754 moles.
0.25 moles
1 mole occupies 22.414 liters So, 3.30 moles will occupy 73.966 liters.
Assuming ideal behaviour, 1 mole of any gas occupies 22.4L at STP. So, moles of 10L = 10/22.4 moles = 0.4464 moles
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NH3 is not liquid but gas at STP. It is however very well soluble in water, solution called ammonia.
The answer is 0,2675 moles.
The answer is 2,68 moles.