16,8 L of Xe gas at STP is equivalent to 0,754 moles.
0.25 moles
8,4 liters of nitrous oxide at STP contain 2,65 moles.
The answer is 0,2675 moles.
152
Ideal gas equation. PV = nRT ===============
PV = nRT ⟹ n = PV/RT = 1 * 18.65 / (0.082 * 273.15) = 0.8321 moles.
0.25 moles
8,4 liters of nitrous oxide at STP contain 2,65 moles.
See the Related Question "How do you solve Ideal Gas Law problems?" to the left for the answer.
The answer is 2,68 moles.
The answer is 0,2675 moles.
Approx 0.223 moles.
17.7
Assuming ideal behaviour, 1 mole of any gas occupies 22.4L at STP. So, moles of 10L = 10/22.4 moles = 0.4464 moles
152
3.058
4,54 L of CO2 have 0,204 moles.