Ideal gas equation.
PV = nRT
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Seventeen moles of hydrogen correspond to 204,75.10e23 atoms.
2 moles of benzene gives 12 moles of hydrogen atoms since benzene is C6H6
Since propane has the formula C3H8, each mole of propane will have 8 moles of hydrogen atoms, so 5 moles of propane will contain 5x8=40 moles of hydrogen.
The answer is 0,19 moles.
0. Hydrogen doesn't "reackt" to form Nitrogen Monoxide.
5 moles
12 moles
Methane (CH4) has four atoms of hydrogen per molecule. If there are 3 moles of methane, then there are 12 moles of hydrogen.
Seventeen moles of hydrogen correspond to 204,75.10e23 atoms.
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
2.5 moles H2O (2 moles H/1 mole H2O) = 5 moles of hydrogen
1.5 moles of Hydrogen. In every mole of H2SO4 (Sulfuric Acid) there are 2 moles of Hydrogen atoms. So, in .75 moles of Sulfuric Acid, there would be 1.5 (double the moles of sulfuric acid) moles of Hydrogen.
2 moles of benzene gives 12 moles of hydrogen atoms since benzene is C6H6
0,565 moles
Since propane has the formula C3H8, each mole of propane will have 8 moles of hydrogen atoms, so 5 moles of propane will contain 5x8=40 moles of hydrogen.
At standard temperature and pressure, 1 mole of any gas will occupy 22.4 liters. Set up a direct proportion of 22.4 liters/1 mole = 1 liter/x moles and solve for x. You get 0.045 moles.
The answer is 0,19 moles.