The answer is 7,18.10e-10 moles.
The number of molecules in 0.24 moles of oxygen can be calculated using Avogadro's number, which states that there are 6.022 x 10^23 molecules in one mole of any substance. Therefore, there are approximately 1.45 x 10^23 molecules of oxygen in 0.24 moles.
23 grams iron ( 1mole Fe/55.85 grams) = 0.41 moles of iron
The reaction is :- 2C2H6 + 7O2 ----------> 4CO2 + 6H2O When one mole ethane is combusted 7/2 moles of oxygen are used. When 3 moles of ethane are combusted 3 x 7/2 moles of oxygen used. No. of oxygen molecules consumed =6.022 x 1023 x7/2= 21.077 x 1023=2.107 x 1024 molecules.
It is just as the number.It has 6.5 moles in it
12.044e+23 moleculs
23 moles of oxygen contain 138,509.10e23 molecules.
Diphosphorus pentoxide has 5 oxygen atoms per molecule according to the given prefix. So, 5 moles of it will be 5 x 5 x (6.022x10^23) = 1.51x10^25 oxygen atoms.
very roughly 5 moles...avagadros number = 6.022 x 1023 just devide 30 by this number
One mole is 6.02 × 1023 of anything. One mole of atoms is 6.02 × 1023 atoms, one mole of rice is 6.02 × 1023 grains, one mole of shoes is 6.02 × 1023 shoes.So you multiply 23 with 6.02 × 1023 to get 1.38 × 1025
The number of molecules in 0.24 moles of oxygen can be calculated using Avogadro's number, which states that there are 6.022 x 10^23 molecules in one mole of any substance. Therefore, there are approximately 1.45 x 10^23 molecules of oxygen in 0.24 moles.
one mole of oxygen = 16grams and is 6.02x10^23 atoms one milligram of oxygen is 0.001 grams. number of moles = mass used/ RMM of compound therefore number of moles = 0.001/16 =6.25x10^-5 moles used. to convert to number of atoms multiply by avagadros number. 6.25x10^-5 * 6.02x10^23 3.763x10^19 atoms
14.0 g x 1 mole/187.56 g = 0.0746 moles0.0746 moles Cu(NO3)2 x 6 moles O/mole Cu(NO3)2 = 0.448 moles O atoms0.448 moles O atoms x 6.02x10^23 atoms/mole = 2.70x10^23 atoms of oxygen
1.50 X 10^23/6.022 X 10^23 = 0.249 moles of whatever
23 grams iron ( 1mole Fe/55.85 grams) = 0.41 moles of iron
.565 MOLES
Mass of Aluminum Sulfate: 2.74g Molar Mass of Aluminum Sulfate: 342.14 g/mol Therefore, number of moles of Oxygen can be calculated by 2.74g * 12/342.14 g/mol = 0.096 moles Now since u have the moles of Oxygen, the number of oxygen atoms is given by 0.096 mol * (6.02*10^23) particles or atoms/mol that gives u about 5.78 * 10^22 atoms of oxygen
Atomic Weight sodium = 23 so 46/23 = 2 moles of sodium in 46.0g