Potassium (chemical symbol K) has atomic number 39.1.
Amount of K in 449g sample = 449/39.1 = 11.5mol
There are 11.5 moles of potassium in a 449g sample.
To find the number of moles in 449 g of potassium, divide the given mass by the molar mass of potassium. The molar mass of potassium (K) is approximately 39.10 g/mol. Therefore, 449 g divided by 39.10 g/mol is approximately 11.49 moles of potassium.
1,5 moles of potassium carbonate have 276,41 g.
This mass is 42,28 g.
Molecular weight of potassium (K): 39.1 g/mole...Just divide 156 by the molecular weight to get moles:156/39.1 = 3.99 moles K
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
The molar mass of potassium (K) is approximately 39.1 g/mol. Using this molar mass, we can calculate the weight of 35.1 moles of potassium by multiplying the molar mass by the number of moles. Therefore, 35.1 moles of potassium would weigh approximately 1371.41 grams.
449 g K x 1 mole K/39 g K = 11.5 moles (3 sig figs)
449 (g K) / 39.1 (g/mol K) = 11.5 mol K
12 g of potassium is equivalent to 0,307 moles.
34,7 moles of potassium 1 356,7 g.
In potassium dichromate (K2Cr2O7), there are 7 oxygen atoms per molecule. Therefore, two moles of K2Cr2O7 would contain 14 moles of oxygen atoms. Each mole of oxygen atoms has a molar mass of approximately 16 grams, so there would be 224 grams of oxygen in two moles of potassium dichromate.
242.594 g
0.4g/mol
1,5 moles of potassium carbonate have 276,41 g.
The answer is 224,24 g oxygen.
This mass is 42,28 g.
Molecular weight of potassium (K): 39.1 g/mole...Just divide 156 by the molecular weight to get moles:156/39.1 = 3.99 moles K
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed