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Al + 3AgNO3 ==> Al(NO3)3 + 3Ag
0.75 moles AgNO3 will produce 1/3 x 0.75 moles of Al(NO3)3 b/c of the mole ratio in the balanced eq.
1/3 x 0.75 = 0.25 moles Al(NO3)3 will be produced.

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Q: How many moles of AL(NO3)3 will be produced when 0.75 moleof AGNO3 reacts?
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