Not many!
5.0 grams CaBr2 (1 mole/199.88 grams CaBr2)
= 0.025 moles CaBr2
To find the number of moles of CaBr2 in 5.0 grams, you first need to calculate the molar mass of CaBr2. The molar mass of CaBr2 is 200.8 g/mol. Divide the given mass by the molar mass to find the number of moles: 5.0 g / 200.8 g/mol = 0.025 moles of CaBr2. Since there is one mole of CaBr2 for every two moles of CaBr, you have half of that amount in moles of CaBr: 0.025 moles / 2 = 0.0125 moles of CaBr.
moles = weight in grams / molecular weight = 72 / 180 = 0.4 moles
To find the number of moles in 355 grams of Au, you need to divide the given mass by the molar mass of gold (Au). The molar mass of Au is approximately 197 grams/mol. Therefore, 355 grams of Au is equivalent to 355/197 = approximately 1.80 moles of Au.
To calculate the number of moles in 42 grams of CO2, we first need to find the molar mass of CO2, which is approximately 44 grams per mole. Then, divide the given mass by the molar mass to find the number of moles. In this case, 42 grams of CO2 is equivalent to 42/44 = 0.955 moles.
To find the number of moles of K2SO4 in 15.0 grams, first calculate the molar mass of K2SO4 (K: 39.10 g/mol, S: 32.07 g/mol, O: 16.00 g/mol). Molar mass of K2SO4 = 2(39.10) + 32.07 + 4(16.00) = 174.26 g/mol Now, divide the given mass by the molar mass to find the number of moles: 15.0 g / 174.26 g/mol = 0.086 moles of K2SO4
1 mole of P4O10 reacts with 6 moles of water to produce 4 moles of H3PO4. Therefore, 10.0 moles of water will produce (10/6)*4 moles of H3PO4. To convert moles to grams, multiply the number of moles by the molar mass of H3PO4.
0,31 moles of anhydrous CaBr2 is equal to 61,966 g.
2.5 mol x 10-2
To find the number of moles in 1.2 kg of calcium bromide, you first need to determine the molar mass of calcium bromide (CaBr2), which is approximately 199.89 g/mol. Then convert the mass of 1.2 kg to grams (1200 g). Finally, divide the mass in grams by the molar mass to find the number of moles. In this case, 1200g / 199.89g/mol ≈ 6 moles of calcium bromide.
16 grams of oxygen how many moles is 0,5 moles.
3.5M / 1000, x 150 = how many moles you need. = .525 moles. moles = mass / molec mass. molec mass if cabr2 is 199.86 g/mol. .525 x 199.86 is 104.93g CaBr2
That is a lot of calcium bromide we are dealing with. The formula mass of calcium bromide, CaBr2 is 40.1 + 2(79.9) = 199.9.Amount of CaBr2 = (7.4 x 1000)/199.9 = 32.0mol There are 32 moles of calcium bromide in a 7.4kg pure sample.
53 grams ÷ 18.01 grams/mole = 2.94 moles
.75 moles times 64 grams/mols = 48 grams
180 grams of water is 10 moles of water.
120 grams of calcium contain 2,994 moles.
1,8 grams of fluorine is equivalent to 0,0947 moles.
500 grams of radium is equal to 2,21 moles.