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The answer is o,1 mol.
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Moles of H2SO4 in 20 ml of 4M solution?
The answer is 0,08 mol.
How many moles of Na2CO3 are there in 10.0 L of 2.0 M soluton?
Molarity = moles of solute/Liters of solution Or, for our purposes, Moles of solute = Liters of solution * Molarity Moles Na2CO3 = 10.0 Liters * 2.0 M = 20 moles Na2CO3 --------------------------
What is the molarity of 10 moles of salt dissolved in 20 liters of water?
Molarity = moles of solute/Liters of solution Molarity = 10 moles salt/20 Liters solution = 0.50 M salt solution ----------------------------
How many moles are present in a sample of H2SO4 with a mass of 9.8g?
20 g NaOH is equivalent to 20(g) /[23+16+1](g/mol) = 0.5 mol NaOHThis will react with 0.5 mol H+ which is present in 0.25 mol H2SO4For this you'll need 0.25(mol) /2.0(mol/L) = 0.125 L = 125 mL of 2.0 M H2SO4-solution.
How many moles of sodium hydroxide are required to neutralize 20 mol of nitric acid?
20 moles of NaOH needed to neutralize 20 moles of nitric acid
Moles of H2SO4 in 20 ml of 4M solution?
The answer is 0,08 mol.
How many moles of Na2CO3 are there in 10.0 L of 2.0 M soluton?
Molarity = moles of solute/Liters of solution Or, for our purposes, Moles of solute = Liters of solution * Molarity Moles Na2CO3 = 10.0 Liters * 2.0 M = 20 moles Na2CO3 --------------------------
What is the molarity of 10 moles of salt dissolved in 20 liters of water?
Molarity = moles of solute/Liters of solution Molarity = 10 moles salt/20 Liters solution = 0.50 M salt solution ----------------------------
How many moles of He are 1.201025 atoms He?
20 moles
How many moles are present in a sample of H2SO4 with a mass of 9.8g?
20 g NaOH is equivalent to 20(g) /[23+16+1](g/mol) = 0.5 mol NaOHThis will react with 0.5 mol H+ which is present in 0.25 mol H2SO4For this you'll need 0.25(mol) /2.0(mol/L) = 0.125 L = 125 mL of 2.0 M H2SO4-solution.
How many oxygen atom are in 5 molecules oh H2so4?
Five molecules of H2SO4 contains 20 atoms of Oxygen
How many moles of sodium hydroxide are required to neutralize 20 mol of nitric acid?
20 moles of NaOH needed to neutralize 20 moles of nitric acid
How many atoms are in 2.0 mol of H2SO4?
the density of Na2Co3 is about 2.54 g/cm3. so, the mass of it would be about 2.54*20=50.8 g. 50.4 divided 6.23*1023 equals to 8.08*10-23 mol
How many moles in 20g of magnesium nitrate?
There are 0.13 moles in 20 grams of magnesium nitrate.
How many moles of lithium hydroxide are required to react with 20 mol of CO2?
40 moles of LiOH
How do you make 0.02N sulfuric acid solution?
I would like to dilute some 5N sulfuric acid with water, and make 0.1N sulfuric acid solution. I want 1000ml of 0.1N . I think it's a 50 to 1 ration, but just want to make sure. <Volume of concentrated> x <Concentration of Concentrated> = <Volume of dilute> x <Concentration of dilute> Therefore, <Volume of concentrated> = <Volume of dilute> x <Concentration of dilute> / <Concentration of dilute> = 1000 mL x 0.1 N / 5N = 20 mL. Meaning: Dilute 20 mL of the 5N H2SO4 to 1000 mL in a volumetetric flask will give you 1000 mLs of 0.1 N H2SO4 (aq.).
What is the Amount of benzoic acid to be neutralized by 20 mL NaOH solution in both moles and grams?
We need to know the Molarity (or Molality or formality) of both the acid and the NaOH solution in order to answer this question.
