0.8 moles HNO3 (63.018 grams/1 mole HNO3)
= 50 grams nitric acid
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The mass of 3.80 mol H2O would be 0.2375. This is a math problem.
No, chemistry.
0.80molesN2*(3molesH2/1moleN2)=2.40 moles
The mass of 0.5 moles of H2 is 2 g.
2.00 mol He x 4.00 g/mol = 8.00 grams
1.6 g
36g
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
The formula for water is H2O: Molar mass = 18.02 g / mol H2OIn one mole of H2O there are 2 mol H and 1 mol O:2 mol H1.010 g H = 2.020 g H1 mol H1 mol O16.00 g O = 16.00 g O1 mol OThe percentage of each element is calculated from the quantities in 1 mole as:% element = g element 100g H2O% H...=...2.020 g H... 100......=...11.21 % H18.02g H2O% O...=...16.00 g O... 100......=...88.79 % O18.02g H2ONote: 11.21 + 88.79 = 100.00
1.08x10^22
an equation showing conservation of mass of reactants and products:2H2O --> 2H2 & O2what is the mass of the oxygen gas produced, from 178.8 g H2O , (using molar masses:178.8 g H2O @ (1mol O2)(@ 32.00 g/mol) / (2molH2O)(18.02g/mol) =your answer (4 sigfigs): 158.8 g O2178.8 g H2O ---> 20.0 H2 & 158.8 O2
Convert the 200 mol of water to kilograms of water.
H2O's molar mass is 18 g/mol.
Molar mass of H2O = 18.01528 g/mol
200 (mol) * 56.0 (g/mol) = 11,200.0 grams
You calculate it by using Avogadro's number: 6.022 x10 23 which is one mole of substance. 1.00 x 1024 divided by 6.022 x 1023 = 10 divided by 6.022 = 1.661 mol H2O Use the molar mass of water (18.02 g mol-1) to get to the mass in grams. 18.02 g x 1.661 mol = 29.93 g H2O
18g/mol
36.41% = .3641 g of H2O 63.59% = .6359 g of MnCl2 .6359g MnCl2 x (1molm MnCl2/125.84g MnCl2)=.0051 mol MnCl2 .3641g H2O x (1 mol H2O/ 18.02g H2O) = .0202 mol H2O .0051 mol MnCl2 / .0051 = 1mol MnCl2 .0202 mol H2O /.0051 = 3.96 = 4 mol H2O Formula is: MnCl2 4H2O Manganese (II) chloride tetrahydrate
in order to find the mass of H20 you need the molar mass which is 18.01g/mol and to calculate the mass you just multiply by the number of moles. 18.01 * .20 = 3.60g
1.54 moles H2O (18.016 grams/1 mol H2O ) =27.7 grams
You begin with 1.63 g of MgCl2•xH2O. You end up with 0.762 g MgCl2. That means you lost 1.63 - 0.762 = 0.87 g of H2O. 0.762 g MgCl2 / 95.21 g (molar mass) = .00800 mol MgCl2 0.87 g H2O / 18.02 g (molar mass) = .048 mol H2O x = mol solute / mol solvent x = .048 mol H2O / .00800 mol MgCl2 x = 6 MgCl2•6H2O
24g H2 x 1 mol H2 x 2 mol H2O x 18g H2O/ 2g H2 x 2 mol H20= 216 g H2O 160g O2 x 1 mol O2 x 2 mol H2O x 18g H2O/ 32g O2 x 1 mol O2 x 1 mol H2O= 180 g H2O
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O