You use the Mole-to-Mole ratio. If the equation is 2CH4 + 2H2O = 6H2 + 2CO, then you would start with your given, 8.0 mol CO and multiply that with your mol-to-mol ratio which is (2mol CO/ 2 mol CH4). Your answer will be 8.0 mol.
I assume you mean this reaction.
2H2 + O2 --> 2H2O
5.0 moles O2 (2 mole H2/1 mole O2)
= 10 moles H2 required here
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ks omak
Some conversion required. (mmolar into mol, or moles into mmol ) Molarity = moles of solute/Liters of solution 100 millimolar = 0.1 M glycine Molarity = moles of solute/Liters of solution manipulate algebraically Liters of solution = moles of solute/Molarity 0.005 mole glycine/0.1 M glycine = 0.05 Liters ( 1000 ml/1 L) = 50 milliliters of solution --------------------------------
Molarity = moles of solute/Liters of solution Molarity = 25 moles sucrose/50 liters H2O = 0.5 M sucrose
To convert grams to moles you need mercury's atomic mass: 200.59 grams/mole. You can then take your measurement and divide it by the atomic mass to get moles.Grams ÷ Atomic mass = Moles50.15 grams ÷ 200.59 grams = 0.2500 moles Hg
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 25 mole of CO2 has 25 moles of carbon atoms and 50 moles of oxygen atoms.
Molarity = moles of solute/volume of solution 0.450 M = m/200ml = 90 millimoles, or, what we need; 0.09 moles 0.09 moles NaOH (39.998 grams NaOH/1 mole NaOH) = 3.60 grams of NaOH needed
The answer is 50 moles SiO2.
0.758 moles of NH3 is the amount of moles in 50 grams of NH42SO4.
50 g of NaCl represent 0,856 moles.
50 mL = 0.05 L (6.0 moles/L) × (0.05 L) = 0.3 moles
.15/1000 * 50 = 0.0075 moles or 7.5mmol
Molarity = moles of solute/Liters of solution ( 50 ml = 0.05 Liters ) 12 M HCl = moles HCl/0.05 Liters = 0.60 moles HCl
See the Related Question (link to the left of this answer)."How many moles of carbon dioxide are there in a 50.0 dm3 sample of the gas at a pressure of 100.0 kPa and a temperature of 50 degrees celsius?" 1.86 moles
The answer is 50 mL.
There are 50 moles in 5 liters of 10 M LiCl (10 molar lithium chloride).
Some conversion required. (mmolar into mol, or moles into mmol ) Molarity = moles of solute/Liters of solution 100 millimolar = 0.1 M glycine Molarity = moles of solute/Liters of solution manipulate algebraically Liters of solution = moles of solute/Molarity 0.005 mole glycine/0.1 M glycine = 0.05 Liters ( 1000 ml/1 L) = 50 milliliters of solution --------------------------------
we know, 50 mM = 50/1000 moles per litre = 0.05 moles no. of moles = weight in grams/ weight of one mole weight of one mole of sodium acetate (CH3COONa) = 83g per mole no. of moles = 50/1000 = 0.05 moles thus weight in grams = 0.05*83 = 4.15 g
For this you need the atomic (molecular) mass of KCl. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. KCl= 74.6 grams50.0 grams KCl / (74.6 grams) = .670 moles KCl