You must add 10-5.49 - 10-8.94 - 10-7 = 3.24*10-6 - 1.15*10-9 -1.00*10-7 = 3.1*10-6 mol/L H3O+
1.25 moles of Lithium Chloride
Molarity is calculated as moles of solute divided by volume of solution in liters. In this case, you have 2 moles of sodium chloride in a 0.5 liter solution. So the molarity would be 2 moles / 0.5 L = 4 M.
The molarity of solution is the number of moles of solute per liter of solution. M (molarity ) = n / V = moles of solute / liters of solution = x.xxx M Thus, solutions can have different molarities because they can have different amounts of solute (in moles) per liter of solution.
The concentration in moles of a substance in the solution
By using a 2Molar solution.
1.25 moles of Lithium Chloride
Molarity is calculated as moles of solute divided by volume of solution in liters. In this case, you have 2 moles of sodium chloride in a 0.5 liter solution. So the molarity would be 2 moles / 0.5 L = 4 M.
The 0.5M and 2M refer to moles per liter (of solution). Volume of final solution is 2.5 L + 500 mL = 2.5 L + 0.5 L = 3.0 L. So find out how many moles the final solution has and divide by 3.0L.First solution (0.5 moles/liter)*(2.5 liter) = 1.25 moles2nd solution (2 moles/liter)*(0.5 liter) = 1 moleMolarity: (1.25 mole + 1 mole)/(3.0 liter) = 0.75 moles/liter = 0.75 M
Depends on the concentration of the solution and what is in it.
The molarity of a solution is the number of moles of a solute per liter of its solution. The normality of a solution is the number of gram equivalent weight of a solute per liter of its solution. As I said before, and precisely, Molarity is moles of solute per VOLUME of solution!
300.0 ml of water is added to .40 L of a .400 M Na2CrO4 solution what is the molarity of the resulting solution? Na2CrO4 = 2 Cr +Cr + 4 O's Molar mass = (2*23 + 52 + (4*16) = 162 A .400 M N Na2CrO4 solution has .400 moles of Na2CrO4 in a liter of water. .400 moles of Na2CrO4 = 0.400 * 162 = 64.8 grams of Na2CrO4 in a liter of water. Since you only have .40 L, you have 64.8 grams/liter * 0.4L = 25.92 grams of Na2CrO4 in 0.4 liter of solution. When you add 300.0 ml of water, you have total of 700 ml of solution. You still have 25.92 grams of Na2CrO4, but now you have 700 ml of solution. Molarity = moles of solute per liter of solution. Moles of solute = grams of solute ÷ Molar mass of solute Moles of solute = 25.92 ÷ 162 = 0.16 moles of Na2CrO4. Molarity = 0.16 moles of Na2CrO4 ÷ 0.700 L of solution. Molarity = 0.23 M
The molarity of solution is the number of moles of solute per liter of solution. M (molarity ) = n / V = moles of solute / liters of solution = x.xxx M Thus, solutions can have different molarities because they can have different amounts of solute (in moles) per liter of solution.
If it is 5 molar: 5 moles per liter, then you start with 5 moles of salt. You will always have 5 moles of salt, but it is spread among a bigger volume. So you want it to be 2 moles per liter, so the amount of salt is 2*V, but we know that there are 5 moles, so we have 2*V = 5, and V = 5/2 = 2.5 Liters. Since we started with 1 liter, we must add 1.5 liters.
The concentration in moles of a substance in the solution
pH is 8
moles per liter.
Moles of solute per liter of solution.