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You must add 10-5.49 - 10-8.94 - 10-7 = 3.24*10-6 - 1.15*10-9 -1.00*10-7 = 3.1*10-6 mol/L H3O+

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Q: How many moles of H3O must be added to one liter of a solution to adjust the pH from 8.94 to 5.49?
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