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First you need a balanced equation: Al2O3 + 6HCl -> 2AlCl3 + 3H2O

then you do a simple mole conversion: 1mol HCL/1 X 1mol Al2O3/ 6mol HCl which is (1 X 1) / (1 X 6) = 1/6mol Al2O3 is needed.

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12y ago
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14y ago

2 AL + 6HCl -> 2AlCl3 + 3H2

Three times as much HCl is needed by unit to react with the Al. 2.4 * 3 = 7.2

7.2 moles of HCl

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13y ago

It depends on how much of the acid there is.

It would take one mole of, though, for each mole of a monoprotic acid.

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11y ago

14

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11y ago

3

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Q: How many equivalents of HCL will react with aluminum hydroxide?
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