The number of atoms is 45,166.10e23.
2.5 x 3 / 2 = 3.75 moles of N2
10.08 moles (there are six carbon atoms per molecule of C6H6, hence, six times the number of moles of carbon can be produced).
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
0,044 moles of NH3 can be produced.
1,4 moles carbon monoxide are produced.
2NaN3 --> 2Na + 3N22.88 mol of NaN3 reacted * (3 mol of N2 produced / 2 mol of NaN3 reacted) =4.32 mol of N2
The thermal decomposition reaction is:2 KO2------------K2O2 + O20,2 moles of O2 are produced from o,4 moles KO2.
13.0 cubic feet is equivalent to .3681 cubic meters, which is equivalent to 368.1 liters. At 1.25 grams/liter, there are 460.1 grams. Nitrogen gas has a molar mass of 28.0134 g/mol, so there are 16.4 moles of N2. The equation for the decomposition of NaN3 is 2 NaN3 --> 2 Na + 3 N2. So, for every 3 moles of N2, there must have been 2 moles of NaN3, hence there was 10.9 moles. With a molar mass of 65.01 g/mol, there were 709 grams of NaNO3 to begin with.
10.08 moles (there are six carbon atoms per molecule of C6H6, hence, six times the number of moles of carbon can be produced).
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
6 moles COULD be produced
1,4 moles of CO are produced.
The molecular mass of NH3 is the sum of the atomic mass of nitrogen and three times the atomic mass of hydrogen, or 14.007 + 3(1.008) = 17.031. Therefore, the number of moles of NH3 in 14.0 grams is 14.007/17.031 = 0.822. Since each molecule of N2 supplies two nitrogen atoms and each molecule of NH3 needs only one nitrogen atom, the number of moles of N2 needed is half the number of moles of NH3 formed = 0.411.
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
Answer: 8 mol NO First, you start by writing the decomposition of N2O2CL2: N2O2Cl2=> 2NO +Cl2 (in reality, we should expect NO2 or N2 and O2 to be products in place of NO, but we'll assume the problem given expects this decomposition) Then, using stochiometry: 4 mol N2O2Cl2 * 2 mol NO/1 mol N2O2Cl2= 8 mol NO
0,044 moles of NH3 can be produced.
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?