1 mole NaCl = 6,02×1023
7.5 x (6,022 ×1023 )
1,726.1023 formula units; the expression molecules is not adequate for ionic compounds because they form large lattices.
The answer is 0,274 mole.
.27 mol
The molecular mass of NaCl (as formula unit) is 58,44 g.
No, there will be more molecules in the 50 grams of NaCl, because its molacular weight is lower. NaCl has a molaculair mass of 58.44 g/mol and MgCl2 has a molcular mass of 95.21 g/mol. 50 g / 58.44 g/mol = 0.86 mol NaCl 50 g / 95.21 g/mol = 0.53 mol MgCl2 The avogadro contstant states that 1 mole equals 6.02214179*1023 molecules. So you have 0.86 * 6.022*1023 = 5.18*1023 molecules of NaCl and 0.53 * 6.022*1023 = 3.19*1023 molecules of MgCl2.
We just use stoichiometry. The molecular formula for sodium chloride is NaCl. First we must find the molar mass of NaCl, using the molar masses of each element in the compound. So, 23 g/mol of Na + 36 g/mol of Cl = 58 g/mol of NaCl. Next, we take the amount of grams you have (26 grams) and divide it by the molar mass of NaCl to find the number of moles in your sample. 26 g NaCl / 58 g/mol of NaCl = .45 mol NaCl. Finally, we convert that to the number of NaCl molecules in a mole by multiplying .45 moles by 6.02x1023. This equals 2.7x1023 molecules. Because, technically, NaCl is made up of 2 atoms per molecule, you can multiply that by 2, giving 5.7x1023 atoms.
Weight of NaCl used (250g)/Total molecular weight x Avagadro's number = total molecules of NaCl.
Molecular mass of NaCl = 23.0 + 35.5 = 58.5 Amount of NaCl = 42/58.5 = 0.718mol
The answer is 4,328.1023formula units (not molecules).
1 mole of NaCl: Na = 1 * 22.99 g = 22.99 g Cl = 1* 35.45 g = 35.45 g Total = 58.44 g 238 g NaCl * (1 mol NaCl/58.44 g NaCl) = 4.07 mol NaCl There are approximately 4.1 moles in 238 grams of sodium chloride.
1.31*.3=.393 mols NaCl. This also equals .393(22.99+35.45)=22.97 g NaCl.
The molar mass of NaCl is 58.44 g/mol The molar mass of KCl is 74.5513 g/mol This is because the Potassium atom (K) is heavier than the Sodium atom (Na). Thus one gram of NaCl will contain more molecules (formula units) than one gram of KCl.
5 % NaCl is equal to 5 g NaCl in 100 g of a material.
1 mole of NaCl is 58.44 g 200 g NaCl * (1 mol NaCl/58.44 g NaCl) = 3.422 mol NaCl There are about 3.4 moles in 200 grams of NaCl.
58 g NaCl = 58 (g) / 58.44 (g/mol NaCl) = 0.9925 (mol NaCl) = 0.9925 (mol Cl-) = 0.9925 * 35.45 (g/mol Cl-) = 35.2 g Cl-