Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters )
For our purposes, Moles of solute = Liters of solution * Molarity
Moles NaCl = 0.300 Liters * 0.15 M
= 0.05 moles NaCl
=============
Molarity = moles of solute/Liters of solition
(300 ml = 0.300 Liters )
0.40 M NaCl = moles NaCl/0.300 Liters
= 0.120 moles NaCl
0.40 moles NaCl (58.44 grams/1 mole NaCl)
= 23 grams sodium chloride
=================
.73 moles
257g
234 grams
72.0 grams NaCl (1 mole NaCl/58.44 grams) = 1.2 moles of sodium chloride
molecular formula for sodium chloride = NaClIf the mole (n) for NaCl = 5.3 moles, then the mole of sodium (Na) = 5.3 moles as well. 1 to 1 ratio mass = moles X molar mass m = 5.3 x 22.9 = 121.37 grams of sodium in 5.3 moles of sodium chloride
23.3772 grams are there in four tenths moles of sodium chloride
0,40 moles of sodium chloride contain 23,376 g.
.73 moles
257g
20.67 grams NaCl (1mol NaCl/58.44 g NaCl) = 0.3537 moles of sodium chloride
234 grams
72.0 grams NaCl (1 mole NaCl/58.44 grams) = 1.2 moles of sodium chloride
molecular formula for sodium chloride = NaClIf the mole (n) for NaCl = 5.3 moles, then the mole of sodium (Na) = 5.3 moles as well. 1 to 1 ratio mass = moles X molar mass m = 5.3 x 22.9 = 121.37 grams of sodium in 5.3 moles of sodium chloride
There are 9.3504 grams of Sodium Chloride. Calculations: 0.160 mol NaCl (58.44g/mol) = 9.3504g NaCl
10 moles of sodium chloride have 584,397 g.
The mass is 467,52 g.
If 4,00 is 4,00 moles the answer is 233,759 g NaCl.