Chemistry
Acids and Bases

How many moles of NaCl are present in 300ml of 0.15m solution?

181920

Top Answer
User Avatar
Wiki User
Answered
2012-03-30 01:16:16
2012-03-30 01:16:16

Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters )

For our purposes, Moles of solute = Liters of solution * Molarity

Moles NaCl = 0.300 Liters * 0.15 M

= 0.05 moles NaCl

=============

001
๐ŸŽƒ
0
๐Ÿคจ
0
๐Ÿ˜ฎ
0
๐Ÿ˜‚
0
User Avatar

Related Questions



You need the molar solution to get the number of moles present in 6.52g of Zinc Sulfate.



Molarity = moles of solute/Liters of solution ( get moles of HNO3 and 300 ml = 0.300 Liters ) 0.31 grams Nitric acid (1 mole HNO3/63.018 grams) = 0.004919 moles HNO3 Molarity = 0.004919 moles HNO3/0.300 Liters = 0.0164 M HNO3


Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============


Molarity = moles of solute/Liters of solution ( 22.0 ml = 0.022 Liters ) moles of solute = Molarity * Liters of solution Moles of NaCl = 0.500 M * 0.022 Liters = 0.011 moles of sodium chloride -------------------------------------------


Molarity = moles of solute/Liters of solution ( 50.0 ml = 0.05 Liters ) 0.552 M KCl = moles/.0.05 liters = 0.0276 moles of KCl


An 0.010 M HF solution gives pH = 2.6, so 0.0022 molesare present in 0.22 L




Molarity = moles of solute/Liters of solution ( 20.0 ml = 0.02 Liters ) moles of solute = Liters of solution * Molarity 0.02 Liters * 0.800 M MgCl2 = 0.016 moles MgCl2 -------------------------------


Molarity = moles of solute/Liters of solution ( 25 ml = 0.025 Liters ) 1.5 M KBr = moles KBr/0.025 Liters = 0.038 moles potassium bromide ------------------


Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Algebraically manipulate, moles of solute = Liters of solution * Molarity Moles KMnO4 = (0.075 Liters)(0.0950 M) = 7.13 X 10 -3 moles KMnO4 ------------------------------------


Molarity = moles of solute/liters of solution or, for our specific purpose here moles of solute (HCl) = liters of solution * Molarity 10 ml = 0.01 liters moles of solute (HCl) = (0.01 liters)*(0.1 M HCl) = 0.001 moles of HCl ------------------------------




0.29M = 0.29 moles in 1000 ml so 0.29 x 110/1000 = 0.0319 moles



How many moles of H+ ions are present in the following aqueous solution? 1,410 mL of 0.32 M nitric acid




Molarity = moles of solute/Liters of solution 0.300 M Na3PO4 = moles Na3PO4/2.50 Liters = 0.75 moles Na3PO4



Molarity = moles of solute/Liters of solution ( 24.5 mL = 0.0245 L)Rearranged,moles of solute = Liters of solution * MolarityMoles NaOH = (0.0245 L)(0.130 M NaOH)= 3.19 X 10 -3 moles NaOH==================




Copyright ยฉ 2020 Multiply Media, LLC. All Rights Reserved. The material on this site can not be reproduced, distributed, transmitted, cached or otherwise used, except with prior written permission of Multiply.