1st Get the balanced equation
NaOH + HCl -> NaCl + H2O
Find the number of moles in HCl;
n = cv
n = 0.46x0.61
n = 0.2806 moles
the number of moles of HCl and NaOH is the same so 0.2806moles will be needed
to solve this you must have the molecular weight of NaoH and you can get this by add the molar masses together (H=1 , O=16 , Na-23 ) then multiply the no of moles by the molecular mass that is for mole gram conversion so you have (23+16+1)= 40 and already you have multiplied (2.40)=80 then 2 . 40 = 120 then 80 / 40 = 2 the answer is 2
There is 0.5 moles of NaOH per litre To calculate 0.5 molar NaOH first know the molecular weight of NaOH i.e 40 now multiply the number of moles of NaOH you have (0.5) found as above. so to find the number of grams of NaOH we needed to start with (0.5) * (40) = 20g So dissolve 20g of NaOH in one litre of the solution to prepare 0.5 molar solution
First you have to find the molar mass of NaOH which is, 23+16+1=40g/mol. Then you take 0.450M X 200mL=90 mM. which can be converted to .090 moles just move the decimal three decimal places. Then you take you molar mass which is 40g/mol X .090moles= 3.6grams. (The moles cancelled themselves out and your left with grams.) Pretty easy once you practice more problems.
To do this, you need to know the molecular weight of the element you're dealing with, by adding up the atomic weights of the elements involved (found on any periodic table). The molecular weight is the mass in grams of the compound in one mole - this will provide you with a conversion factor. So take the measurement in grams and divide it by the molecular weight to convert to moles. Really what you're doing is multiplying the number by 1 mole, and dividing it by the equivalent of one mole, the molecular weight. That's the thought process behind unit analysis and how you get your "units to cancel".In this case, the answer is about 2 grams NaOH.
Take 10 ml of 1 N NaOH and dilute to 1000 ml with D.I. H2O
For this you need the atomic (molecular) mass of NaOH. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaOH= 40.083.0 grams NaOH / (40.0 grams)= 2.08 moles NaOH
2.00 M NaOH = 2 moles NaOH/litermolar mass NaOH = 40 g/mole2 moles/liter x 40 g/mole = 80 g/liter(x L)(80 g/L) = 32.0 gx = 0.4 liters = 400 mls needed
to solve this you must have the molecular weight of NaoH and you can get this by add the molar masses together (H=1 , O=16 , Na-23 ) then multiply the no of moles by the molecular mass that is for mole gram conversion so you have (23+16+1)= 40 and already you have multiplied (2.40)=80 then 2 . 40 = 120 then 80 / 40 = 2 the answer is 2
There is 0.5 moles of NaOH per litre To calculate 0.5 molar NaOH first know the molecular weight of NaOH i.e 40 now multiply the number of moles of NaOH you have (0.5) found as above. so to find the number of grams of NaOH we needed to start with (0.5) * (40) = 20g So dissolve 20g of NaOH in one litre of the solution to prepare 0.5 molar solution
The answer is 97,66 moles.
First you have to find the molar mass of NaOH which is, 23+16+1=40g/mol. Then you take 0.450M X 200mL=90 mM. which can be converted to .090 moles just move the decimal three decimal places. Then you take you molar mass which is 40g/mol X .090moles= 3.6grams. (The moles cancelled themselves out and your left with grams.) Pretty easy once you practice more problems.
The nunber of moles of oxygen is 2,5.
10
To do this, you need to know the molecular weight of the element you're dealing with, by adding up the atomic weights of the elements involved (found on any periodic table). The molecular weight is the mass in grams of the compound in one mole - this will provide you with a conversion factor. So take the measurement in grams and divide it by the molecular weight to convert to moles. Really what you're doing is multiplying the number by 1 mole, and dividing it by the equivalent of one mole, the molecular weight. That's the thought process behind unit analysis and how you get your "units to cancel".In this case, the answer is about 2 grams NaOH.
The answer is 2,68 moles.
Take 10 ml of 1 N NaOH and dilute to 1000 ml with D.I. H2O
how many tums tablets each 250mg calcium carbonate would it take to neutralize a quart of vinegar 0.83m acetic acid