5.56
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
The chemical formula of the anhydrous copper(II) sulfate is CuSO4. The molar mass is 159,609. The percentage of oxygen is 40,25 %, or 64,245 g.64,245 g oxygen (O2) is equal to cca. 2 moles.
There are 0.003659 N2O moles. So there are o.007318 moles of N.
3 moles of O, so that must be 6 moles of O2
The mass in grams of 3,20 moles of copper is 158,865 g.
5.56
The answer is 159,62 g for the anhydrous salt.
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
This ratio is 1:2.
One molecule has 6 individual atoms. If the number you are looking for is much larger than that you need to know how many grams or moles of CuSO4 you are supposed to calculate.
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.
0.25 Pb(NO3)2 + CuSO4 --> PbSO4 + Cu(NO3)2 stoichiometry is 1:1 for Pb(NO3)2 : CuSO4
0.515 moles
The chemical formula of the anhydrous copper(II) sulfate is CuSO4. The molar mass is 159,609. The percentage of oxygen is 40,25 %, or 64,245 g.64,245 g oxygen (O2) is equal to cca. 2 moles.
CuSO4 (cupric sulfate) has a molecular weight of 159.602g/mol Cu=63.546 S =32.06 O = 15.999 x 4 =63.996 Add the atomic weights of the elements in cupric sulfate. This is 159.602 grams/mol. Now divide the number of grams( 44.78) by the molecular weight of cupric sulfate (159.602). 44.78 g CuSO4/159.602 g/mol CuSO4= .2805 mol(moles) of cupric sulfate. The answer is 0.2805
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